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vodomira [7]
3 years ago
9

Which could be the value of x in the triangle below?

Mathematics
1 answer:
hjlf3 years ago
8 0
C could be the answer
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Suppose the point (x,y )is tranlated horizontally c units.
algol13
The new position is then (x+c, y).
3 0
3 years ago
Evaluate the following pic
GREYUIT [131]

Answer:

1) \sqrt{1225}+\sqrt{1024}=67

2)  \sqrt[3]{-1331}=-11

3) Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

Step-by-step explanation:

1) \sqrt{1225}+\sqrt{1024}

Prime factors of 1225 : 5x5x7x7

Prime factors of 1024: 2x2x2x2x2x2x2x2x2x2

\sqrt{1225}+\sqrt{1024}\\=\sqrt{5\times5\times7\times7}+\sqrt{2\times2\times2\times2\times2\times2\times2\times2\times2\times2}\\=\sqrt{5^2\times7^2}+\sqrt{2^2\times2^2\times2^2\times2^2\times2^2}\\=5\times7+(2\times2\times2\times2\times2)\\=35+32\\=67

\sqrt{1225}+\sqrt{1024}=67

2) \sqrt[3]{-1331}

We know that \sqrt[n]{-x}=-\sqrt[n]{x} \ ( \ if \ n \ is \ odd)

Applying radical rule:

\sqrt[3]{-1331}\\=-\sqrt[3]{1331} \\=-\sqrt[3]{11\times\11\times11}\\=-\sqrt[3]{11^3} \\Using \ \sqrt[n]{x^n}=x \\=-11

So, \sqrt[3]{-1331}=-11

3) 2:p :: p:8

It can be written as:

p*p=2*8\\p^2=16\\Taking \ square \ root \ on \ both \ sides\\\sqrt{p^2}=\sqrt{16}\\p=\pm 4

Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6

Put value of x, y and z in equation and solve:

x^3+y^2+z \\=(3)^3+(-2)^2+(-6)\\=27+4-6\\=25

So, x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}

We know (-a)^n = (a)^n when n is even and (-a)^n = (-a)^n when n is odd

\frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}\\\\=\frac{1296\times-8\times 27}{46656}\\\\=\frac{-279936}{46656} \\\\=-6

So, \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

8 0
3 years ago
Solve for x 4x - 4 < 8
UNO [17]

Answer:

x < 3

Step-by-step explanation:

Yup

5 0
3 years ago
Read 2 more answers
28 POINTS!!!!!! Solve for x. Please Help
elena-14-01-66 [18.8K]
The correct answer is the first option which is negative 2
7 0
3 years ago
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In March 2007​, the U.S. unemployment rate was 4.4 percent. In August 2008​, the unemployment rate was 6.1 percent. Predict what
Luba_88 [7]

Answer:

Increased.

Step-by-step explanation:

In March 2007, the unemployment rate was 4.4 percent. In August 2008 was 6.1 percent. We need to remember that the unemployment rate equals the number of unemployed people divided by the people in the labor force.

Now, if we consider that the labor force remained constant during this period of time (according to the problem) then this would mean that the number of unemployed people actually increased during this period of 17 months.

4 0
3 years ago
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