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Volgvan
3 years ago
14

For f(x)=2x − 3 , for what value(s) of x does f(x) = 13?

Mathematics
2 answers:
Deffense [45]3 years ago
5 0

Answer:

Step-by-step explanation:

2x - 3 = 13

2x = 10

x = 5

kogti [31]3 years ago
3 0

f(x) = 2x - 3, for f(x) = 13

13 = 2x - 3

Add 3 to both sides.

16 = 2x

Divide both sides by 2

8 = x

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A map scale shows that 2 inches represents 90 miles. How many inches would represent 315 miles ?
bezimeni [28]

Answer:

7

Step-by-step explanation:

315/90x2

4 0
3 years ago
Read 2 more answers
The ability of lizards to recognize their predators via tongue flicks can often mean life or death for lizards. Seventeen juveni
Sloan [31]

Answer:

Confidence level is (380.7133, 533.2867)

Step-by-step explanation:

Responses in number of tongue flicks per 20 minutes of lizards, are: 727,217, 268, 438, 625, 319, 200, 591, 574, 727, 693, 336, 302, 761, 268, 353, 370

n = 17

Mean (μ) is:

\mu=\frac{{\Sigma}x}{n} = \frac{727+217+ 268+ 438+ 625+ 319+ 200+ 591+ 574+ 727+ 693+ 336+ 302+ 761+ 268+ 353+ 370}{17} = 439.3529

Standard deviation (σ) is:

\sigma=\sqrt{\frac{\Sigma(x-\mu^2)}{n} } =\sqrt{\frac{(727-457)^2+(217-457)^2+...+(370-457)^2}{17} } =191.2

The confidence interval (c) = 90% = 0.9

\alpha=1-0.9=0.1\\\frac{\alpha }{2} = 0.05\\Z_{\frac{\alpha }{2} }=1.64

Margin of error (e) = =Z_{\frac{\alpha}{2} }*\frac{\sigma}{\sqrt{n} }=1.64*\frac{191.2}{\sqrt{17} }=76.2867

Confidence level = μ ± e = 457 ± 76.2867 = (380.7133, 533.2867)

8 0
4 years ago
Please help I really don't get this I will give you 131 points that are all of them HELP ME SOON
zlopas [31]
The answer is 120 seconds.

Why?
180 divided by 4.5 is 40 seconds
200 divided by 2.5 is 80 seconds
Then add the seconds.
But I don’t understand how you walk so many meters in 180 seconds
4 0
3 years ago
If a company changes from full-cost pricing to variable-cost pricing but retains the same markup percentage, their net income wi
NeX [460]
If a company changes from full-cost pricing to variable cost pricing but retains the same markup percentage, their net income will likely increase. Although variable cost pricing is risky since the price will be dependent on the other factors of the product. 
3 0
3 years ago
When dealing with the number of occurrences of an event over a specified interval of time or space, the appropriate probability
sdas [7]

Answer:

a)  Poisson distribution

use a  Poisson distribution model when events happen at a constant rate over time or space.

Step-by-step explanation:

<u> Poisson distribution</u>

  • Counts based on events in disjoint intervals of time or space produce a Poisson random variable.
  • A Poisson random variable has one parameter, its mean λ
  • The Poisson model uses a Poisson random variable to describe counts in data.

use a  Poisson distribution model when events happen at a constant rate over time or space.

<u>Hyper geometric probability distribution</u>:-

The Hyper geometric probability distribution is a discrete probability distribution that describes the probability of successes (random draws for which the object drawn has a specified feature) in draws without replacement, from a finite population of size that contains exactly objects with that feature where in each draw is either a success or failure.

This is more than geometric function so it is called the <u>Hyper geometric probability distribution </u>

<u></u>

<u>Binomial distribution</u>

  • The number of successes in 'n' Bernoulli trials produces a <u>Binomial distribution </u>. The parameters are size 'n' success 'p' and failure 'q'
  • The binomial model uses a binomial random variable to describe counts of success observed for a real phenomenon.

Finally use a Binomial distribution when you recognize distinct Bernoulli trials.

<u>Normal distribution</u>:-

  • <u>normal distribution is a continuous distribution in which the variate can take all values within a range.</u>
  • Examples of continuous distribution are the heights of persons ,the speed of a vehicle., and so on
  • Associate normal models with bell shaped distribution of data and the empirical rule.
  • connect <u>Normal distribution</u> to sums of like sized effects with central limit theorem
  • use histograms and normal quantile plots to judge whether the data match the assumptions of a normal model.

<u>Conclusion</u>:-

Given data use a  Poisson distribution model when events happen at a constant rate over time or space.

3 0
3 years ago
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