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Volgvan
3 years ago
14

For f(x)=2x − 3 , for what value(s) of x does f(x) = 13?

Mathematics
2 answers:
Deffense [45]3 years ago
5 0

Answer:

Step-by-step explanation:

2x - 3 = 13

2x = 10

x = 5

kogti [31]3 years ago
3 0

f(x) = 2x - 3, for f(x) = 13

13 = 2x - 3

Add 3 to both sides.

16 = 2x

Divide both sides by 2

8 = x

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Answer:

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Step-by-step explanation:

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3 years ago
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Find the coordinates of the missing endpoint if m is the midpoint of ab. a(-9, -4) and m(-7, -2.5)
Julli [10]

Answer:

The coordinates of the point b are:

b(x₂, y₂)  = (-5, -1)

Step-by-step explanation:

Given

As m is the midpoint, so

m(x, y) = m (-7, -2.5)

The other point a is given by

a(x₁, y₁) = a(-9, -4)

To determine

We need to determine the coordinates of the point b

= ?

Using the midpoint formula

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

substituting (x, y) = (-7, -2.5), (x₁, y₁) = (-9, -4)

\left(-7,\:-2.5\right)=\left(\frac{x_2+\left(-9\right)}{2},\:\:\frac{y_2+\left(-4\right)}{2}\right)

Thus equvating,

Determining the x-coordinate of b

[x₂ + (-9)] / 2 = -7

x₂ + (-9) = -14

x₂ - 9 = -14

adding 9 to both sides

x₂ - 9 + 9 = -14 + 9

x₂ = -5

Determining the y-coordinate of b

[y₂ + (-4)] / 2 = -2.5

y₂ + (-4) = -2.5(2)

y₂ - 4 = -5

adding 4 to both sides

y₂ - 4 + 4 = -5 + 4

y₂ = -1

Therefore, the coordinates of the point b are:

b(x₂, y₂)  = (-5, -1)

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6 0
3 years ago
Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)
Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}

By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}

6 0
3 years ago
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Help please. this is really hard for me to understand.
bogdanovich [222]

Answer:

1. x = - 4, - 3

2. x = 9, - 1

3. x = - 1, 10

4. x = - 8, - 3

8 0
3 years ago
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