I will show you how to do the first one.....we are finding the GCF...the largest number that goes into each number (same for variables)
1.) 20yx , 80x³ ( factor each number and variable)
20 = 2, 4, 5, 10, 20
y = y
x = x
80 = 2, 4, 5, 8, 10, 16, 20, 40, 80
x³ = x, x, x
what is the largest number that 20 and 80 have in common? 20...
how about the variables? x
so, the Greatest Common Factor (GCF is 20x)
First we need slope
Put D co-ordinates on y=mx+b
Now
slope intercept form.
Answer:
261 km
Step-by-step explanation:
given,s=constant
d1/T1=d2/T2
d1=90km,t1=50 min
d2=? ,t2=(120+25)min
=145min
therefore,d2=(90×145)/50
=261 km
Answer:
In order of least money saved to most money saved: Katrina, Susan, Gabrielle, Savanna
Step-by-step explanation:
You can first change all of them to either percentages or fractions with the same denominator. I chose to use percentages. Thus Savanna's percentage of money saved would be 90%, Katrina would've saved 80% and Susan would've saved around 83%.
From here you just order from least to greatest.
Answer:
Option E is correct.
The expected number of meals expected to be served on Wednesday in week 5 = 74.2
Step-by-step Explanation:
We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.
Week
Day 1 2 3 4 | Total
Sunday 40 35 39 43 | 157
Monday 54 55 51 59 | 219
Tuesday 61 60 65 64 | 250
Wednesday 72 77 78 69 | 296
Thursday 89 80 81 79 | 329
Friday 91 90 99 95 | 375
Saturday 80 82 81 83 | 326
Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952
Total number of meals served at lunch on Wednesdays over the 4 weeks = 296
Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443
Total number of meals expected to be served in week 5 = 490
Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3
Checking the options,
74.3 ≈ 74.2
Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2
Hope this Helps!!!
