Answer:
d. x = 5
Step-by-step explanation:
Solve for x:
x - 3 = 7 - x
Hint: | Move terms with x to the left hand side.
Add x to both sides:
x + x - 3 = (x - x) + 7
Hint: | Look for the difference of two identical terms.
x - x = 0:
x + x - 3 = 7
Hint: | Add like terms in x + x - 3.
x + x = 2 x:
2 x - 3 = 7
Hint: | Isolate terms with x to the left hand side.
Add 3 to both sides:
2 x + (3 - 3) = 3 + 7
Hint: | Look for the difference of two identical terms.
3 - 3 = 0:
2 x = 7 + 3
Hint: | Evaluate 7 + 3.
7 + 3 = 10:
2 x = 10
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 2 x = 10 by 2:
(2 x)/2 = 10/2
Hint: | Any nonzero number divided by itself is one.
2/2 = 1:
x = 10/2
Hint: | Reduce 10/2 to lowest terms. Start by finding the GCD of 10 and 2.
The gcd of 10 and 2 is 2, so 10/2 = (2×5)/(2×1) = 2/2×5 = 5:
Answer: x = 5
The height of the platform would be the last part of the equation
45 feet
Answer with step-by-step explanation:
The way the question is worded, this actually shouldn't be correct. The correct answer should be
.
Because the trapezoids are similar, we can find the ratio of their perimeters by actually just finding the ratio of their sides.
Why?
By definition, the corresponding sides of a polygon are in a constant proportion. The perimeter is simply the sum of all sides of the polygon. Since we're just adding the sides, the proportion will still be maintained.
Therefore, we'll just need to ratio of their corresponding sides. The only two corresponding sides that are marked are
and
.
The ratio of
is
.
The reason why it ideally should be
and not
is because the question states
, which mentions
first, so our answer should follow this respective order. I believe you were marked right anyways because the specific order is not specified, but generally, you want to give your answer respectively by default.
Answer: x<17.5
Step-by-step explanation:
Subtract from both sides: x+2.5-2.5<20-2.5
Simplify the arithmetic: x<20-2.5
Simplify the arithmetic: x<17.5
Hope it helps!
Wavelength denotes the time for one cycle of a periodic process