Answer:
#section 1
def maxTemp(filename):
import pathlib
f = pathlib.Path(filename)
f.exists()
if f.exists():
f = open(filename, "r")
#section 2
next(f)
res = [int(sub.split(',')[1]) for sub in f]
maxdata = (res[0])
for i in range(len(res)-1):
if maxdata < res[i]:
maxdata = res[i]
index = res.index(maxdata)
f.close()
#section 3
li = []
a = open(filename, "r")
for line in a:
line = line.strip()
li.append(line)
a.close()
return (li[index+1])
else:
return -1
print(maxTemp("new.csv"))
Explanation:
#section 1:
The function maxTemp is defined. We import pathlib in other to check if the file exists, if it does we carry on with opening the file and if it doesn't the program returns -1.
#section 2:
We start splitting the sub-lists from the second line i.e <em>next(f)</em>. For each line we take the second index element and convert it to an integer.
<em>res = [int(sub.split(',')[1]) for sub in f]
</em>
The maximum number is gotten by using the if statement to compare all elements in the list. The index of the maximum item in the list is collected.
the file is then closed.
#section 3 :
The file is re-opened and all the lines are striped and passed into a new list and the index recovered from section 2, is used to get the day with the highest temperature and the line is returned.
The Hierarchical drawing of the In- House solutions includes Four categories such as product, service, training, support and about.
<h3>What is Hierarchical drawing?</h3>
Hierarchical drawing is also known as Layered Graph Drawing which includes the drawing in the vertices and are made on the Horizontal rows and layers.
The complete solution is attached below.
The In-House solutions' hierarchical diagram covers four categories, including product, service, training, support, and about.
Learn more about Hierarchical drawing here:
brainly.com/question/26031625
#SPJ1
Answer:
Technology > Network report. All traffic > Source/Medium report.
Explanation:
hope this helps
Answer:
#include <iostream>
using namespace std;
void PrintPopcornTime (int bagOunces){
if (bagOunces < 2){
cout << "Too small"<<endl;
}
else if (bagOunces > 10){
cout << "Too large"<<endl;
}
else{
cout << bagOunces*6 <<" seconds"<<endl;
}
}
int main(){
PrintPopcornTime(7);
return 0;
}
Explanation:
Create a function called PrintPopcornTime that takes one parameter, bagOunces
Check the bagOunces using if-else structure. If it is smaller than 2, print "Too small". If it is greater than 10, print "Too large". Otherwise, calculate and print 6*bagOunces followed by " seconds".
Call the function in the main function with parameter 7. Since 7 is not smaller than 2 or not greater than 10, "42 seconds" will be printed.
