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Readme [11.4K]
4 years ago
13

We will pass in 2 values, X and Y. You should calculate XY XY and output only the final result. You will probably know that XY X

Y can be calculated as X times itself Y times. # Get X and Y from the command line:import sysX= int(sys.argv[1])Y= int(sys.argv[2])# Your code goes here
Computers and Technology
1 answer:
kiruha [24]4 years ago
5 0

Answer:

import sys

# The value of the second argument is assigned to X

x = int(sys.argv[1])

# The value of the third argument is assigned to Y

y = int(sys.argv[2])

# The result of multiplication of x and y is assigned to 'result'

result = x * y

#The value of the result is displayed to the user

print("The result of multiplying ", x, "and ", y, "is", result)

Explanation:

First we import sys which allow us to read the argument passed when running the program. The argument is number starting from index 0; the name of the python file been executed is sys.argv[0] which is the first argument. The second argument is sys.argv[1] and the third argument is sys.argv[2].

The attached file is named multplyxy (it wasn't  saved as py file because the platform doesn't recognise py file); we can execute it by running: python3 multiplyxy.py 10 23

where x will be 10 and y will be 23.

To run the attached file; it content must be saved as a py file: multiplyxy.py

Download pdf
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Plato :
ddd [48]

Answer:

filler content

Explanation:

Isabel must use some sort of filler content while creating a wireframe that she is up with. For the banner, she can make use of the placeholder, and for the text, she can make use of the lorem ipsum. Also, if the wireframe is low fidelity then only she can use above. And if the wireframe is high fidelity then she should use the original banner and text.

3 0
3 years ago
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In the second example with modulus math, why can't Eve find the solution?
Leno4ka [110]
C. She would have to resort to trial and errors to find a matching exponent
6 0
3 years ago
T in your computer will you use to plug in your camera?
Gnom [1K]
A tool in your computer that you will use to plug in your camera is the Universal Serial Bus (USB). If you camera has this chord and it is an Universal Serial Bus type. Then what you need is your software installer of the camera and only the USB.
7 0
4 years ago
7.12 LAB: Even/odd values in a list
Korvikt [17]

The odd values in a list can be calculated by knowing the first and last number, whereas even numbers can be divided by two and the remainder is zero (0).

<h3>What are even numbers and odd numbers?</h3>

The even numbers can be found in a list because they are divisible by two and the remainder of this equation is always zero (0).

Conversely, odd numbers are those that cannot be divided exactly into exact entire numbers (e.g., 3, 5, etc).

The odd numbers in a list can be calculated by the equation ON (odd numbers): n/2 × [f + g], where 'f' is the first number and 'g' is the last number.

In conclusion, the odd values in a list can be calculated by knowing the first and last number, whereas even numbers can be divided by two and the remainder is 0.

Learn more about odd numbers here:

brainly.com/question/2263958

#SPJ1

4 0
2 years ago
Define a method calcPyramidVolume with double data type parameters baseLength, baseWidth, and pyramidHeight, that returns as a d
Rudik [331]

Answer:

import java.io.*;

public class Main {

   public static void main(String[] args) throws IOException {

       double baseLength = 0, baseWidth = 0, pyramidHeight = 0;

       Object[] volume;

       volume = calcPyramidVolume(baseLength, baseWidth, pyramidHeight);

   }

   public static Object[] calcPyramidVolume(double baseLength, double baseWidth, double pyramidHeight) {

       double area = calcBaseArea(baseLength, baseWidth);

       double volume = baseLength * baseWidth * pyramidHeight;

       return new Object[]{volume, area};

   }

   public static double calcBaseArea(double length, double width) {

       return length * width;

   }

}

Explanation:

The problem is flawed because it is completely inefficient for one to create two separate methods to calculate the volume and the area when they can be done at once.

The second problem is that it was never specified whether to return something from the calcBaseArea method.

I assumed it required it, so it is not advisable to initiate the method as a double, but rather create it as an Object so that it can return two values: the volume and the area.

6 0
3 years ago
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