Answer:
The fraction of the original strip left is
.
Step-by-step explanation:
We have that,
A strip of paper is cut in
. So, the strip of paper left is
.
Now, again the remaining part is cut in half. The part left will be
i.e.
.
Finally, the remaining part is again cut in half.
We get, the final part of the paper remaining is
i.e.
.
So, the fraction of the original strip left is
.
This is the concept of areas of solid figures. The surface are of the solid figure formed when 2 square pyramids are attached will be given by:
SA=[number of triangular faces]*[Area of each triangle]
Number of triangular faces=8
Area of each triangle=1/2*bh
base=6/4=1.5 cm
height=2 cm
thus;
Area=1/2*2*1.5=1.5
The surface area will therefore be:
SA=1.5*8=12cm^2
Answer:
The least common multiple of 30, 25, 4 is 150.
Step-by-step explanation:
The given numbers are 30, 25 and 4.
The factors of given numbers are
![30=2\times 3\times 5](https://tex.z-dn.net/?f=30%3D2%5Ctimes%203%5Ctimes%205)
![30=5\times 5](https://tex.z-dn.net/?f=30%3D5%5Ctimes%205)
![4=2\times 2](https://tex.z-dn.net/?f=4%3D2%5Ctimes%202)
The L.C.M of given numbers is a smallest number that divides the given numbers completely.
![L.C.M.=\frac{2\times 3\times 5\times 5\times 5\times 2\times 2}{5\times 2}](https://tex.z-dn.net/?f=L.C.M.%3D%5Cfrac%7B2%5Ctimes%203%5Ctimes%205%5Ctimes%205%5Ctimes%205%5Ctimes%202%5Ctimes%202%7D%7B5%5Ctimes%202%7D)
![L.C.M.=2\times 3\times 5\times 5\times 2=150](https://tex.z-dn.net/?f=L.C.M.%3D2%5Ctimes%203%5Ctimes%205%5Ctimes%205%5Ctimes%202%3D150)
Therefore the least common multiple of 30, 25, 4 is 150.
Answer:
1. x =8
2. x=9
Step-by-step explanation:
Since these figures are parallelograms, the opposite sides are equal.
1. 6 = 2x-10
Add 10 to each side
6+10 = 2x-10+10
16 = 2x
Divide each side by 2
16/2 = 2x/2
8 =x
2. x+14 =23
Subtract 14 from each side
x+14-14 = 23-14
x = 9
<h2>
Answer with explanation:</h2>
Formula for plus-four confidence interval :
![\hat{p}\pm z^* \sqrt\dfrac{\hat{p}(1-\hat{p})}{n+4}}](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%5Cpm%20z%5E%2A%20%5Csqrt%5Cdfrac%7B%5Chat%7Bp%7D%281-%5Chat%7Bp%7D%29%7D%7Bn%2B4%7D%7D)
, where n= Sample size.
= Sample proportion and ![\hat{p}=\dfrac{x+2}{n+4}](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%3D%5Cdfrac%7Bx%2B2%7D%7Bn%2B4%7D)
z* = Critical z-value.
Let p be the proportion of puppies area found with early hip dysplasia.
As per given , we have
n= 42
![\hat{p}=\dfrac{5+2}{42+4}=0.1522](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%3D%5Cdfrac%7B5%2B2%7D%7B42%2B4%7D%3D0.1522)
Since confidence interval is not given , so we assume it as 95% .
z-critical value for 95% confidence is 1.96.
Then, the required confidence interval will become :
![0.1522\pm (1.96)\sqrt{\dfrac{0.1522(1-0.1522)}{42+4}}\\\\ 0.152\pm (1.96)\sqrt{0.002805112173}\\\\ 0.152\pm 0.1038\\\\ =(0.1522- 0.1038 ,\ 0.152+ 0.1038)\approx(0.0484,\ 0.256)](https://tex.z-dn.net/?f=0.1522%5Cpm%20%281.96%29%5Csqrt%7B%5Cdfrac%7B0.1522%281-0.1522%29%7D%7B42%2B4%7D%7D%5C%5C%5C%5C%200.152%5Cpm%20%20%281.96%29%5Csqrt%7B0.002805112173%7D%5C%5C%5C%5C%200.152%5Cpm%200.1038%5C%5C%5C%5C%20%3D%280.1522-%200.1038%20%2C%5C%200.152%2B%200.1038%29%5Capprox%280.0484%2C%5C%200.256%29)
Hence, the plus four confidence interval for p = (0.0484, 0.256)
Interpretation: We are 95% sure that the true proportion of puppies area found with early hip dysplasia lies in (0.0484, 0.256).