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icang [17]
3 years ago
15

Find the quotient of 1+7i/3i in standard form write your answer in standard form

Mathematics
1 answer:
ch4aika [34]3 years ago
3 0
For the first one it would be 10/3 ( 10 over 3 ) and for the second one, it would be 7/13 ( 7 over 13 ) PLUS 4i/13 ( 4i over 13)
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Write each expression in exponential form and find its value 2 x 2 x 2 2 ​
Natasha2012 [34]

Answer:

2^{4}

Step-by-step explanation:

8 0
3 years ago
Please help quick thank you!
ipn [44]

Answer:

Neither

Step-by-step explanation:

After substituting the ordered pair into the equation, none of the pairs satisfy the equation

because 6(3)+3(-2)=12 and 6(2)+3(2)=18.

8 0
3 years ago
Which pair of functions have the same domain? A. F(x)= sin x and g(x) = tan x B. F(x) = cos x and f(x) = csc x C. G(x) = tan x a
EastWind [94]

Answer:

The correct choice is D

Step-by-step explanation:

The trigonometric functions, \sin x and \cos x are defined for all real numbers.

\tan x=\frac{\sin x}{\cos (x)}, this function is not defined where \cos x=0.

\cot x=\frac{\cos x}{\sin (x)}, this function is not defined where \sin x=0.

\csc x=\frac{1}{\sin (x)}, this function is not defined where \sin x=0.

For option A

The domain of f(x)=\sin(x) is all real numbers.

The domain of g(x) =tanx is x\ne \frac{(2n+1)\pi}{2}

For option B

The domain of f(x)=\cos(x) is all real numbers.

The domain of f(x) =csc(x) is x\ne n\pi

For option C,

The domain of G(x) =tanx is x\ne \frac{(2n+1)\pi}{2}

The domain of f(x) =cot(x) is x\ne n\pi

For option D;

The domain of f(x) =cot(x) is x\ne n\pi

The domain of f(x) =csc(x) is x\ne n\pi

3 0
3 years ago
Read 2 more answers
What is a parallel slope for the line y = 2x + 2?
ArbitrLikvidat [17]

Answer: 2

Step-by-step explanation:

The slope is equal to 2 by it being in the slope place of y=mx+b

5 0
3 years ago
Find the equation for the circle with a diameter whose endpoints are (-5, -3) and (3,2).
densk [106]

Answer:

  (x +1)^2 +(y +0.5)^2 = 22.25

Step-by-step explanation:

The center of the circle is the midpoint of the diameter, so is ...

  (h, k) = ((-5, -3) +(3, 2))/2 = (-5+3, -3+2)/2 = (-1, -1/2)

The circle formula is then ...

  (x -h)^2 +(y -k)^2 = r^2

  (x -(-1))^2 +(y -(-1/2))^2 = r^2

We can find r^2 by substituting one of the points for (x, y).

  (3 +1)^2 +(2 +1/2)^2 = r^2 = 16 +6.25 = 22.25

Then the circle equation is ...

  (x +1)^2 +(y +0.5)^2 = 22.25

3 0
3 years ago
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