For an individual die roll, the probability of rolling 6 is \dfrac{1}{6}
6
1
.
Effectively, this problem is asking for P(\text{1st roll is 6}\cap\text{2nd roll is 6})P(1st roll is 6∩2nd roll is 6).
Using the rule of product, this is:
\dfrac{1}{6}\times\dfrac{1}{6}=\dfrac{1}{36}
6
1
×
6
1
=
36
1
.
if you isolate y in the top equation to get y=5x+6 then you can substiture y for 5x+6 in the bottom equation because thats what y equals
as of now you have -3x+6(5x+6)=-12 but if you use the distrubite property you would get -3x+30x+36=-12
then if you subtract 36 from both sides you would get -3x+30x=-48 then combine like terms to get 27x=-48 then divide both sides by 27 to get
or x≈1.8
Answer:
2 square cm
Step-by-step explanation:
Given :
A square is inscribed in a circle whose radius is r = 1 cm
Therefore, the diameter of the circle is 2 r = 2 x 1
= 2 cm.
So the diagonal of the square is 2r.
Using the Pythagoras theorem, we find each of the side of the triangle is
.
Therefore, the area of the square is given by 
= 



Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.
No, because all sides are not congruent. The answer is B.