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postnew [5]
3 years ago
5

A line's slope is 2 ,and its y-intercept is 2. What is its equation in slope -intercept

Mathematics
1 answer:
solong [7]3 years ago
4 0

Answer:

y=2x+2

y=slope x plus y int

so with a slope and y intercept of two that's what you get

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Two sides of a triangle are two consecutive number, whose area is 17.5cm². Find the numbers
AveGali [126]

Answer:

The numbers associated with the triangle are 5.437 and 6.437 centimeters, respectively.

Step-by-step explanation:

Two numbers are consecutives, when their difference is equal to 1. The area of the triangle is determined by the following formula:

A = \frac{1}{2}\cdot n \cdot (n+1)

A = \frac{1}{2}\cdot (n^{2}+n)

A = \frac{n^{2}}{2}+\frac{n}{2}

n^{2}+n = 2\cdot A

Where n is the shortest length of the triangle, measured in centimeters.

And we get the following second-order polynomial:

n^{2}+n -2\cdot A = 0 (1)

If we know that A = 17.5\,cm^{2}, then the shortest length of the triangle is:

n_{1} = 5.437\,cm and n_{2} \approx -6.437\,cm

Since length is a positive variable, the only possible solution is:

n\approx  5.437\,cm

Then, the numbers associated with the triangle are 5.437 and 6.437 centimeters, respectively.

6 0
2 years ago
A set of positive and negative rational numbers is shown.
Troyanec [42]
Answer:1 3/4 < 1 7/8
Showing the workThe least common denominator is 8Comparing 14/8 and 15/8:
14/8 < 15/8     ...       .....                  ...     ....therefore1 3/4 < 1 7/8
5 0
3 years ago
Read 2 more answers
HELP ME ASAP PLEASE
vfiekz [6]

Answer:

144.44

Step-by-step explanation:

C = 2 x π x r .      C = 2 x 3.14 x 23  = 144.44

5 0
3 years ago
Towns P,Q,R and S are shown. Q is 35 km due East of P S is 15km due West of P R is 15km due South of P Work out the bearing of R
Anni [7]

Answer:

Part A

The bearing of the point 'R' from 'S' is 225°

Part B

The bearing from R to Q is approximately 293.2°

Step-by-step explanation:

The location of the point 'Q' = 35 km due East of P

The location of the point 'S' = 15 km due West of P

The location of the 'R' = 15 km due south of 'P'

Part A

To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that \overline{RP} = \overline{SP}, the right triangle ΔRPS is an isosceles right triangle

∴ ∠PRS = ∠PSR = 45°

The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°

Part B

∠PRQ = arctan(35/15) ≈ 66.8°

Therefore the bearing  from R to Q = 270 + 90 - 66.8 ≈ 293.2°

6 0
3 years ago
Simplify -2.3f+0.9f-14-4
Setler [38]

Answer:

The Answer would be 1.4f-18

Step-by-step explanation:

-2.3f+0.9f-14-4

then you do

-1.4f-14-4

Then u would get 1.4f-18.

7 0
3 years ago
Read 2 more answers
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