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AURORKA [14]
3 years ago
6

Write an equation that can be used to solve the following: The sum of a number, n, and a number 5 larger than it is 41.

Mathematics
2 answers:
Naya [18.7K]3 years ago
8 0

Answer:

n + (n+5) = 41

Step-by-step explanation:

The sum of a number, n, and a number 5 larger than it is 41.

n + (n+5) = 41


navik [9.2K]3 years ago
4 0

n + n + 5 = 41 (4) 5n + n + 1 = 41

<em>n and "5 larger than n" </em>

'5 larger than n' = equivalent to n + 5

We now have n + n + 5

The problem says 41, thus;

<em>n + n + 5 = 41</em>

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The radius of the tires of a car is 18 inches, and they are revolving at the rate of 651 revolutions per minute. How fast is the
Mumz [18]
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4 0
3 years ago
An urn contains 5 red, 6 blue, and 8 green balls. If a set of 3 balls is randomly selected, what is the probability that each of
monitta

Answer:

As a fraction, the answer is exactly 86/969

In decimal form, the answer is approximately 0.08875

=====================================================

Work Shown:

The assumption is that no replacements are made for each selection.

5 red, 6 blue, 8 green

5+6+8 = 19 total

A = P(3 red) = (5/19)*(4/18)*(3/17) = 10/969

B = P(3 blue) = (6/19)*(5/18)*(4/17) = 20/969

C = P(3 green) = (8/19)*(7/18)*(6/17) = 56/969

D = P(3 all same color)

D = A+B+C

D = 10/969 + 20/969 + 56/969

D = (10+20+56)/969

D = 86/969

D = 0.08875

6 0
3 years ago
The sum of two numbers is 47 and the difference is 25 . what are the numbers?
taurus [48]
The numbers are:  36 and 11 .
______________________________________________
Explanation:
______________________________________________
Let us represent the TWO (2) numbers with the variables;
         "x" and "y" .
__________________________________________
     x + y = 47 .

     y − x = 25.
__________________________________________
Since:  " y − x = 25 " ;

Solve for "y" in terms of "x" ;

  y − x = 25  ;

Add "x" to each side of the equation:
_____________________________________________
   y − x + x  = 25 + x  ;

to get:

   y = 25 + x .

Now, since:

  x + y = 47 ;

Plug in "(25 + x)" as a substitution for "y"; to solve for "x" :

x + (25 + x) = 47  ;

x + 25 + x + 47 ;

2x + 25 = 47 ;

Subtract "25" from each side of the equation:

2x + 25 − 25 = 47 − 25 ;

2x  = 22  ;

Divide EACH SIDE of the equation by "2" ;
 to isolate "x" on one side of the equation; and to solve for "x" ; 
 
2x / 2 = 22 / 2 ;

    x = 11 ;
______________________________________________
x + y = 47<span> ;

</span>Plug in "11" for "x" into the equation ; to solve for "y" ;

11 + y = 47 ;

Subtract "11" from EACH SIDE of the equation;
  to isolate "y" on one side of the equation; and to solve for "y" ;

 11 + y − 11 =  47 − 11  ;

            y = 36 .
___________________________________________
So:  x = 11 , y = 36 ;
___________________________________________
 Let us check our work:

y − x = 25 ;

36 − 11 =? 25 ?  Yes!

x + y = 47 ;

36 + 11 =? 47 ? Yes!
______________________________________________
The numbers are:  36 and 11 .
______________________________________________
5 0
3 years ago
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