Hello,
1. Since Angle C has the longest side for this triangle, it will have the largest degree value.
2. Use the Law of Cosines and inverse properties of “theta” to solve for Angle C. (Ensure that the calculator used is in “degree mode”, not “radian mode”.
c^2 = a^2 + b^2 - 2(a)(b)(cos (C))
15^2 = 11^2 + 14^2 - 2(11)(14)(cos(C))
225 - 317 = -2(11)(14)(cos(C))
-92 / -2(11)(14) = cos(C)
cos(C) becomes ->> cos^-1[92 /-2(11)(14)] = 72.62° ->> to the nearest degree is 73°
The answer for angle C, 73°, is logical because the triangle in the picture represents a 60-60-60 triangle, known as an equilateral triangle.
Good luck to you!
The answer is both triangles A and D
Hope this helps :)
Triangle ABC has vertices at A(3, 8) , B(11, 8) , and C(9, 12) . Triangle FGH has vertices at F(1, 3) , G(9, 3) , and H(7, 7) .
Alex17521 [72]
Hmm, (x,y)
x is horizontal or left right
y is vertical or up down
so
we see that A to F is move left 2 and down 5
B to G is left 2 and down 5
C to H is left 2 and down 5
so translatete ABC left 2 and down 5 and
translate FGH right 2 and up 5
not 1st option
2nd works
3rd works
4th is false
2nd and 3rd
Answer:
Let R = unit rate
R = (7/8) ÷ 1_1/4
R = (7/8) ÷ (5/4)
R = (7/8) • (4/5)
R = (7/2) • (1/5)
R = 7/10
Step-by-step explanation:
