Answer:
Solving systems of equations with 3 variables is very similar to how we solve systems with two variables. When we had two variables we reduced the system down
to one with only one variable (by substitution or addition). With three variables
we will reduce the system down to one with two variables (usually by addition),
which we can then solve by either addition or substitution.
To reduce from three variables down to two it is very important to keep the work
organized. We will use addition with two equations to eliminate one variable.
This new equation we will call (A). Then we will use a different pair of equations
and use addition to eliminate the same variable. This second new equation we
will call (B). Once we have done this we will have two equations (A) and (B)
with the same two variables that we can solve using either method. This is shown
in the following examples.
Example 1.
3x +2y − z = − 1
− 2x − 2y +3z = 5 We will eliminate y using two different pairs of equations
5x +2y − z = 3
Step-by-step explanation:
Answer:
3x + 2y = 17
2x + 5 y = 26
Step-by-step explanation:
3x + 2y = 17 }
2x + 5 y = 26}
x - 3y = - 9
x = -9 + 3y
=> 2 (-9+3y)+5y=26
-18+6y+5y=26
-18+11y=26
11y=26+18
11y=44
y= 4
3x + 8=17
3x = 17 - 8
3x = 9
x = 9 : 3
x = 3
Y= x/8 rate is 1 to 1/8
hope it helps!!
Answer:
A. Five places to the left
Step-by-step explanation:
Scientific notation is a method used so we can show a very big/small number easier. Rather than putting so many zeroes, we put the number in the format of a number multiplied by 10^x.
Before putting a number into scientific notation, you need to know which number is a significant figures. In this question, there are two significant figure which is 39, all zeroes on the right is insignificant. We can move the decimal to convert the number into 3.9 * 10^5. Basically you need to move the decimal to the left if the exponent positive, but move it to the right if its negative. The exponent is +5 so we move the decimal points 5 places to the left.
Answer:
The only difference is that for any positive value of 'x' g(X) and h(X) will be same and for any negative value of 'x' g(x) and h(x) will be different.
Step-by-step explanation:
Given


|x| is modulus of x so modulus makes negative value as psoitive
for example


now we will solve for the above
For 

and

Now for 

and

so for positive value it is same and for negative value it is different