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4 years ago

Angles formed by transversals: I need the answer to this question ASAP please help me out. Thank You.

Mathematics

1 answer:

Anna [14]4 years ago

4 0

Answer:

148, 32, 32

148, 148, 323

32, 148

Step-by-step explanation:

m<1 = m<4 = m<5 = m< 8 = 180 - 32 = 148 degrees

m<2= m<3 = m<6 = m<7 = 32 degrees

7x+18 = 2x+28

5x = 10

x=2

2*2 +28 = 32

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Plz answer my question

Llana [10]

Answer:

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Step-by-step explanation:

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8 0

4 years ago

A rock is thrown upwards from the top of a building 200 feet high with an initial velocity of 96 feet per second

dmitriy555 [2]

T=3-√ 43/2=-1.63 and 3+√ 43/2=7.63

and since time can't be negative, it hits the ground at 7.63 seconds.

and then for 3 there are two steps. Use t=−b2a to find the time of max height. Then plug that time into the h(t) equation

the same values you used in the quadratic equation a = -16, b = 96, c = 200

t=−962(−16)

344 is the answer.

6 0

3 years ago

Solve each equation for m -5 =8

Diano4ka-milaya [45]

Answer:

m = 13

Step-by-step explanation:

Given

m - 5 = 8 ( isolate m by adding 5 to both sides of the equation )

m = 8 + 5 = 13

3 0

4 years ago

Read 2 more answers

Arsenic is toxic to humans. The greatest amount of arsenic that is allowed in drinking water is 10 parts per billion. A test sho

Anna35 [415]

The decimal you put would be “two ten-millionths” if read out loud. If the allowable amount is 10 parts per billion, it would be 1 part per 100 million. Because 2 parts per 10 million is also 20 parts per 100 million, it is not not an acceptable amount

3 0

3 years ago

Match the expression on the left with the correct simplified expression on the right.

andriy [413]

Given: The expression below

$\begin{gathered} (\frac{(3x^3y^4)^3}{(3x^2y^2)^2})^2 \\ (\frac{(3x^4y^2)^4}{(3x^5y^2)^3})^2 \end{gathered}$

To Determine: The matching expression to the given expressions

Solution

Let us simplify each of the expressions using exponents rule

$\begin{gathered} Exponent-Rule1=(a^m)^n=a^{m\times n} \\ Exponent-Rule2=(\frac{a^m}{a^n})=a^{m-n} \end{gathered}$

Applying the exponent rule 1 above to the given expressions

$\begin{gathered} (3x^3y^4)^3=3^3x^{3\times3}y^{4\times3}=27x^9y^{12} \\ (3x^2y^2)^2=3^2x^{2\times2}y^{2\times2}=9x^4y^4 \end{gathered}$ $\begin{gathered} (3x^4y^2)^4=3^4x^{4\times4}y^{2\times4}=81x^{16}y^8 \\ (3x^5y^2)^3=3^3x^{5\times3}y^{2\times3}=27x^{15}y^6 \end{gathered}$

Applying the exponent rule 2

$\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}}=\frac{27x^9y^{12}}{9x^4y^4}=\frac{27}{9}x^{9-4}y^{12-4}=3x^5y^8$ $\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}}=\frac{81x^{16}y^8}{27x^{15}y^6}=\frac{81}{27}x^{16-15}y^{8-6}=3xy^2$

Let us not apply exponent rule 1 above

$(\frac{(3x^{3}y^{4})^{3}}{(3x^{2}y^{2})^{2}})^2=(3x^5y^8)^2=3^2x^{5\times2}y^{8\times2}=9x^{10}y^{16}$ $(\frac{(3x^{4}y^{2})^{4}}{(3x^{5}y^{2})^{3}})^2=(3xy^2)^2=3^2x^2y^{2\times2}=9x^2y^4$

Hence, the matching is as shown below

8 0

2 years ago