A. Which reduction should she use so the picture fills as much of the frame as possible, without being too large?
Find the scale factor to get rom 7 1/3 inches to 5 1/3 inches:
5 1/3 / 7 1/3 = 0.7272
Now rewrite the fraction as decimals:
2/3 = 0.667
¾ = 0.75
5/9 = 0.555
The closest scale that would still fit the frame would be 2/3 because it is under 0.727.
B. How much extra space is there in the frame when she uses the reduction from Part A?
Multiply the original size by the scale factor to use:
7 1/3 x 2/3 = 4 8/9
Now subtract the scaled size from the original size:
7 1/3 – 4 8/9 = 2 4/9 inches extra
C. If she had a machine that could reduce by any amount, so that she could make the reduced picture fit in the frame exactly, what fraction would the reduction be?
Convert the scale from part A to a fraction:
0.72 = 72/99 which reduces to 8/11
Answer:
B,C,D
Step-by-step explanation:
24ft =288 in A IS FALSE
2 miles = 10560 ft B IS TRUE
1/2 miles = 2640 ft C IS TRUE
0.5 miles = 880 Yds D IS TRUE
0.5 ft = 6 in E IS FALSE
ANSWER
36,-36
EXPLANATION
The given function is:
![f(x) = {x}^{2} + 12x + 6](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%2012x%20%2B%206)
To write this function in vertex form;
We need to add and subtract the square of half the coefficient of x.
The coefficient of x is 12.
Half of it is 6.
The square of 6 is 36.
Therefore we add and subtract 36.
Hence the zero pair is:
36, -36.
The correct answer is D.
Answer:
Statement A is correct about Sam's box and whisker plot.
Step-by-step explanation:
We have been given a box plot and we are asked to find out true statement according to the box plot.
Since we know data represented by box plot is divided in four equal parts.
Upon looking at our box plot we can see that our data is symmetric. It's median is 15, which means half the math assignments have less than 15 problems and half of the math assignments have more than 15 problems.
Interquartile range represents 50% values of data and it is the difference between upper quartile and lower quartile. IQR is not affected by outliers.
![IQR=Q_3-Q_1](https://tex.z-dn.net/?f=IQR%3DQ_3-Q_1)
Upon substituting given values from box plot we get,
![IQR=19-11=8](https://tex.z-dn.net/?f=IQR%3D19-11%3D8)
From IQR we can conclude that half of the assignments contained 15 problems or fewer.Therefore, option A is the correct choice.
Answer:
5 or -5
Step-by-step explanation:
3+2=5
-1(3+2)=-5