What makes up the majority of the solar system<br><br><br><br>space

A cue ball initially moving at 3.4 m/s strikes a stationary eight ball of the same size and mass. After the collision, the cue b

romanna [79]

Answer:

speed of eight ball speed after the collision is 3.27 m/s

Explanation:

given data

initially moving v1i = 3.4 m/s

final speed is v1f = 0.94 m/s

angle = θ w.r.t. original line of motion

solution

we assume elastic collision

so here using conservation of energy

initial kinetic energy = final kinetic energy .............1

before collision kinetic energy = 0.5 × m× (v1i)²

and

after collision kinetic energy = 0.5 × m× (v1f)² + 0.5 × m× (v2f)²

put in equation 1

0.5 × m× (v1i)² = 0.5 × m× (v1f)² + 0.5 × m× (v2f)²

(v2f)² = (v1i)² - (v1f)²

(v2f)² = 3.4² - 0.94²

(v2f)² = 10.68

taking the square root both

v2f = 3.27 m/s

speed of eight ball speed after the collision is 3.27 m/s

5 0

3 years ago

What makes up the large, bright rings of Saturn?

slavikrds [6]

Answer:

The ring particles are made almost entirely of water ice, with a trace component of rocky material.

Explanation:

3 0

3 years ago

A canister is filled with 310 g of ice and 100. G of liquid water, both at 0 ∘c . The canister is placed in an oven until all th

olya-2409 [2.1K]

Here in the process we require

1. Heat to melt down all ice

2. Heat to raise the temperature of whole water to 100 degree C

3. Heat to boil off the water

now here for the first part

Heat required to melt the ice

$Q_1 = mL$

$Q_1 = 310*80 = 24800 cal$

now heat required to raise the temperature to 100 degree C

$Q_2 = ms\Delta T$

$Q_2 = (310 + 100)*1*(100 - 0)$

$Q_2 = 41000 cal$

Now heat required to boil it off

$Q_3 = mL$

$Q_3 = 410*540 = 221400 cal$

now the total heat required will be

$Q = Q_1 + Q_2 + Q_3$

$Q = 24800 + 41000 + 221400$

$Q = 287200 cal$

so it required 287200 calorie heat to boil it all water

6 0

3 years ago

Why do we feel cool when we spray perfume in our body

KiRa [710]

Because the perfume is sprayed as a fine mist. This exposes a lot of its surface area to air, causing it to evaporate quickly. That makes us feel cooler.

5 0

4 years ago

Read 2 more answers

A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V?

SpyIntel [72]

Answer:

U= $0.112 x10^{-6}$ J

u= 0.708 $\frac{J}{m^{3} }$

Explanation:

diameter= 2 cm

$r= 1 cm * \frac{1m}{100cm} = 0.01 m$

distance= 0.5 mm

$d= 0.5 mm * \frac{1m}{1000m}= 0.5 x10^{-3}$

Area A= $\pi *r^{2}= 0.314x10^{-3} m^{2}$

Volume v= $A*d = 0.314 x10^{-3}m^{2}*0.5x10^{-3} m =0.157x10^{-6} m^{3}$

$v= 0.157 x10^{-6} m^{3}$

Constant vacuum permittivity

$E_{o}= 8.85x10^{-12}$

a).

$C= \frac{A*E_{o} }{d} = \frac{0.314x10^{-3} *8.85x10^{-12} }{0.5x10^{-3} } \\C= 5.56 x10^{-12}$ F

$U= \frac{1}{2} *C *V^{2}\\ U=\frac{1}{2} * 5.56x10^{-12}*(200)^{2} \\U=0.112 x^{-6} J\\$

b).

$u=\frac{U}{v}$

$u=\frac{0.112 x10^{-6}J}{0.157x10^{-6}m^{3} } \\u=0.708 \frac{J}{m^{3} }$

5 0

4 years ago

What makes up the majority of the solar systemspace