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3 years ago

Which of the following is NOT a way that machines provide a mechanical advantage?

2 answers:

4 0

The following choice that is NOT a way that machines provides a mechanical advantage is to change direction. The correct answer is A.

Mumz [18]3 years ago

4 0

i just took the test, A is incorrect.

im guessing its C, but not certain

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Assignment

Igoryamba

Answer:

step bro was stuck on the elevator

Explanation:

5 0

2 years ago

A parallel beam of light in air makes an angle of 43.5 ∘ with the surface of a glass plate having a refractive index of 1.68. Yo

aniked [119]

Answer:

a) 46.5º b) 64.4º

Explanation:

To solve this problem we will use the laws of geometric optics

a) For this part we will use the law of reflection that states that the reflected and incident angle are equal

θ = 43.5º

This angle measured from the surface is

θ_r = 90 -43.5

θ_s = 46.5º

b) In this part the law of refraction must be used

n₁ sin θ₁ = n₂. Sin θ₂

sin θ₂ = n₁ / n₂ sin θ₁

The index of air refraction is n₁ = 1

The angle is this equation is measured between the vertical line called normal, if the angles are measured with respect to the surface

θ_s = 90 - θ

θ_s = 90- 43.5

θ_s = 46.5º

sin θ₂ = 1 / 1.68 sin 46.5

sin θ₂ = 0.4318

θ₂ = 25.6º

The angle with respect to the surface is

θ₂_s = 90 - 25.6

θ₂_s = 64.4º

measured in the fourth quadrant

3 0

3 years ago

A 1.1 kg ball is attached to a ceiling by a 2.16 m long string. The height of the room is 5.97 m . The acceleration of gravity i

nydimaria [60]

1. -23.2 J

The gravitational potential energy of the ball is given by

$U=mgh$

where

m = 1.1 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration of gravity

h is the height of the ball, relative to the reference point chosen

In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is

h = -2.16 m

And the gravitational potential energy is

$U=(1.1 kg)(9.8 m/s^2)(-2.16 m)=-23.2 J$

2. 41.1 J

Again, the gravitational potential energy of the ball is given by

$U=mgh$

In this part of the problem, the reference point is the floor.

The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:

h = 5.97 m - 2.16 m = 3.81 m

And so the gravitational potential energy of the ball relative to the floor is

$U=(1.1 kg)(9.8 m/s^2)(3.81 m)=41.1 J$

3. 0 J

As before, the gravitational potential energy of the ball is given by

$U=mgh$

Here the reference point is a point at the same elevation of the ball.

This means that the heigth of the ball relative to that point is zero:

h = 0 m

And so the gravitational potential energy is

$U=(1.1 kg)(9.8 m/s^2)(0 m)=0 J$

4 0

3 years ago

A force of 10.0 newtons acts at an angle 20.0 degrees from vertical. What are the horizontal and vertical components of the forc

erik [133]

Horizontal component = (10N) · sin (20°) = 3.42... N (rounded)

Vertical component = (10N) · cos (20°) = 9.39... N (rounded)

8 0

3 years ago

Describe a good level of body fat

m_a_m_a [10]

Answer: a good level of body fat can be found using your weight and height as a reference.

Explanation:

6 0

4 years ago