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3 years ago

Highest density of electrostatic charges in a metal is found where

Physics

1 answer:

swat323 years ago

6 0

I don't know the answer but I just want points sorry

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4 years ago

Sitting in a second-story apartment, a physicist notices a ball moving straight upward just outside her window. The ball is visi

gregori [183]

Answer:

1.013 s

Explanation:

You can solve this problem using the equations for constant acceleration motion. The velocity at the bottom of the window can be found using this expression:

$(x-x_o) = \frac{1}{2} at^2 + v_ot = -\frac{1}{2}gt^2 + v_ot$

the gravity is negative as it opposes the movement.

$(x-x_o) = -\frac{1}{2}gt^2 + v_ot\\v_o = \frac{(x-x_o)+\frac{1}{2}gt^2}{t} = \frac{1.19m+\frac{1}{2} 9.81m/s^2(0.2s)^2}{0.2s} = 6.931 m/s$

Now, the time elapsed before the ball reappears is 2 times the time that it takes for the ball to go from the bottom of the window, reach maximum height, and reach again the bottom of the window, minus 2 times the time that it takes for the ball to travel from the top to the bottom of the window. The time that takes to the ball to reach maximum height, or in other words, to time that takes for the velocity of the ball to go from vo to 0m/s:

$t_1 = \frac{0m/s - v_o}{g} = \frac{-6.931 m/s}{-9.81m/s^2} = 0.706 s$

Then:

$t = 2t_1 - 2*0.2s = 2*(0.706s) - 0.4s = 1.013 s$

7 0

3 years ago

A bowling ball with a mass of 7.0kg strikes a pin that had a mass of 2.0kg the pin flies forward with a velocity of 6.0m/s, and

Natalka [10]

The conservation of momentum P states that the amount of momentum remains constant when there are not external forces.

We don't have external forces, so:

$P_0 = P_1\\m_bv_{0b}+m_pv_{0p}=m_bv_{1b}+m_pv_{1p}\\$

Where:

mb is the mass of the bowling ball
mp the mass of the pin
$v_{0b}\quad and\quad v_{0p}$ the initial velocities of the bowling ball and the pin.
$v_{1b}\quad and\quad v_{1p}$ the final velocities of the bowling ball and the pin.

Solving for v0b:

$v_{0b} =\dfrac{m_bv_{1b}+m_pv_{1p}- m_pv_{0p}}{m_{b}}\\\\v_{0b} =\dfrac{(7\;kg)(4\;m/s)+(2\;kg)(6\;m/s)- (2\;kg)(0 \;m/s)}{7\;kg}\\v_{0b}=\dfrac{40}{7}\;m/s\\\\\boxed{v_{0b}\approx5.71\;m/s}$

<h2>R/ The original velocity of the ball was 5.71 m/s.</h2>

6 0

3 years ago

Highest density of electrostatic charges in a metal is found where​

Highest density of electrostatic charges in a metal is found where