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Elena L [17]
3 years ago
11

Highest density of electrostatic charges in a metal is found where​

Physics
1 answer:
swat323 years ago
6 0

I don't know the answer but I just want points sorry

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Assuming things about someone based on your experiences with similar people you have encountered is called
AysviL [449]

Answer:

presumptuous

Explanation:

it's what you call someone who assumes something

3 0
3 years ago
Pen and ink manufacturers are asked to submit their new ink formulations to what database?
Ilia_Sergeevich [38]
The international ink library.
3 0
3 years ago
A spring required a force of 5.0 n to compress it 0.1 m. how much work is required to stretch the spring 0.4 m
lions [1.4K]

Answer:

20N

Explanation:

The force (Hooke's Law) is proportional to the deformation. To extend the spring 4 times longer, you will need 4 times the force. In total, 20 N

5 0
4 years ago
Read 2 more answers
An oil layer that is 5.0 cm thick is spread smoothly and evenly over the surface of water on a windless day. What is the angle o
Fofino [41]

Answer:

32.1

Explanation:

NOTE: You did not state the angle of incidence, and thus, I will be using 45° as my angle of incidence, all you need to do is replace it with your own value if it's different.

To solve this question, we are going to be using Snell's Law.

Snell's law describes the relationship between the angles of incidence and refraction, when referring to light or other waves passing through a boundary between two different isotropic media, such as water, glass, or air.

Snell's law is mathematically given as

sin(A1)/sin(A2) = n2/n1, where

n1 = incidence index

n2 = refracted index

A1 = incidence angle

A2 = refracted angle

The refraction index of oil is 1.15, and that of water is 1.33, so

if we take oil first,

sin A2 = (n1.sinA1)/n2

sin A2 = (1 * sin 45)/1.15

sin A2 = 0.7071/1.15

sin A2 = 0.6149

A2 = sin^-1 0.6149

A2 = 37.9°

Then

sin A3 = (1.15 * sin 37.9) / 1.33

sin A3 = (0.6149 * 1.15) / 1.33

sin A3 = 0.7071 / 1.33

sin A3 = 0.5317

A3 = sin^-1 0.5317

A3 = 32.1

4 0
3 years ago
Carbon-14 has a half life of 5730 years. Consider a sample of fossilized wood that when alive would have contained 24g of C-14 i
kirza4 [7]

Answer:

5732 years

Explanation:

hope it helps, if not im sorry

6 0
3 years ago
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