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denis-greek [22]
3 years ago
5

Why do we feel cool when we spray perfume in our body​

Physics
2 answers:
Lina20 [59]3 years ago
7 0

Answer:

We feel cooler when we spray perfume on our body because the perfume requires latent heat of vaporisation to change its state of matter from liquid to gas and this latent heat is provided by our body. Our body loses heat as it gives its heat in converting perfume from liquid to gas. Hence our body loses heat and becomes cooler.

Hope this helps ;-))

PLEASE CAN YOU GIVE ME BRAINLIEST

KiRa [710]3 years ago
5 0
Because the perfume is sprayed as a fine mist. This exposes a lot of its surface area to air, causing it to evaporate quickly. That makes us feel cooler.
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A cat is sleeping on the dashboard of a moving car. Imagine that the cat does not wake up and is not touched by anything. Use Ne
Minchanka [31]
What do we call an object displaced by an unbalanced Force,
Accelerated object,


And we also know that,
Due to acceleration, An object displaces.

But I'll use Newton's 1st law to prove it,
Which is, An object will remain in rest or in uniform motion until it is compelled by an external Force.

As per the his law,
The cat will remain on the dashboard of that moving car until it is compelled by Air Force (external Force).

!! Hope It Helps !!
7 0
3 years ago
g The steam above a freshly made cup of instant coffee is really water vapor droplets condensing after evaporating from the hot
geniusboy [140]

Answer:

the final temperature = 74.33°C

Explanation:

Using the expression Q = mcΔT for the heat transfer and the change in temperature .

Here ;

Q = heat transfer

m = mass of substance

c = specific heat

ΔT = the change in temperature

The heat Q required to change the phase of a sample mass  m is:

Q = mL_v

where;

L_v  is the latent heat of vaporization.

From the question ;

Let M represent the mass of the coffee that remains after evaporation is:

ΔT = \frac{mL_v}{MC}

where;

m = 2.50 g

M = (240 - 2.50) g  = 237.5 g

L_v  = 539 kcal/kg

c = 1.00kcal/kg. °C

ΔT = \frac{2.50*539 \ kcal /kg}{237.5 g *1.00 \ kcal/kg . ^0C}

ΔT = 5.67°C

The final temperature of the coffee is:

T_f = T_i - ΔT

where ;

T_I = initial temperature = 80 °C

T_f = (80 - 5.67)°C

T_f =  74.33°C

Thus; the final temperature = 74.33°C

8 0
3 years ago
Read 2 more answers
What's the formula to calculate the radius of pendulum bob ​
Svetradugi [14.3K]

Answer:

The combination, L = I / (m * R) , that appears in the equation for the period of a physical pendulum, is called radius of oscillations

Hope this helps :]

7 0
3 years ago
A rock is lifted by a machine to a height of 10m. If it has a mass of 22 kilograms
zmey [24]

Answer:

2156J

Explanation:

Given parameters:

Height of lift  = 10m

Mass  = 22kg

Unknown:

Work done by the machine  = ?

Solution:

Work done is the force applied to move a body through a certain distance.

So;

        Work done  = Force x distance

Here;

       Work done  = mass x acceleration due to gravity x height

      Work done  = 22 x 9.8 x 10  = 2156J

5 0
3 years ago
1. why did aristarchus choose the time of a half (quarter) moon to make his measurements for calculating the earth-sun distance?
Stells [14]

In order to make his measurements for determining the Earth-Sun distance, Aristarchus waited for the Moon's phase to be exactly half full while the Sun was still visible in the sky. For this reason, he chose the time of a half (quarter) moon.

<h3 /><h3>How did Aristarchus calculate the distance to the Sun?</h3>

It was now possible for another Greek astronomer, Aristarchus, to attempt to determine the Earth's distance from the Sun after learning the distance to the Moon. Aristarchus discovered that the Moon, the Earth, and the Sun formed a right triangle when they were all equally illuminated. Now that he was aware of the distance between the Earth and the Moon, all he needed to know to calculate the Sun's distance was the current angle between the Moon and the Sun. It was a wonderful argument that was weakened by scant evidence. Aristarchus calculated this angle to be 87 degrees using only his eyes, which was not far off from the actual number of 89.83 degrees. But when there are significant distances involved, even slight inaccuracies might suddenly become significant. His outcome was more than a thousand times off.

To know more about how Aristarchus calculate the distance to the Sun, visit:

brainly.com/question/26241069

#SPJ4

7 0
1 year ago
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