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elena-14-01-66 [18.8K]
3 years ago
14

During the first part of this lab, we want to determine how the object distance is related to what two quantities

Physics
1 answer:
Nataly [62]3 years ago
4 0

Answer and Explanation:

The computation of the object distance related to two quantities is shown below:

It could find out by using the lens formula which is shown below:

\frac{1}{v}  - \frac{1}{u} = \frac{1}{f}

where,

v = image distance

u = object distance

f = focal length

It could be found by applying the above formula i.e considering the image distance, object distance and the focal length

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If a galaxy has an apparent radial velocity of 2000 km/s and the Hubble constant is 70 km/s/Mpc, how far away is the galaxy
ddd [48]

Answer:

28.57 Mpc

Explanation:

This question is going to be solved by applying Hubble's Law.

This Hubble's Law is actually an observation in physical cosmology. This observation makes it clear that galaxies are moving away from the Earth, and are doing so at speeds proportional to their distance. This essentially means that the farther they are from the Earth, the faster they are moving away from Earth.

It is represented by this formula

v = H(0)D, where

v = speed

H(0) = Constant of proportionality, or otherwise, Hubble's constant.

D = Distance to a galaxy

Applying the given parameters to the formula, we have

v = H(0).D

D = v / H(0)

D = 2000 / 70

D = 28.57 Mpc

3 0
3 years ago
How far can a person run in 15 minutes if he or she runs at an average speed of 16 km/hr
Studentka2010 [4]
4 km/hr. There are four quarters in an hour, so just divide 16 by 4 and you get 4. It is directly proportional.
6 0
3 years ago
A beam of light is emitted 8.6 cm beneath the surface of a liquid and strikes the air surface 7.2 cm from the point directly abo
Makovka662 [10]

Answer:

n = 1.56

Explanation:

The total reflection attempts occurs when a light beam passes from a medium with a higher index to a medium with a lower nest, at an angle where it occurs we can find them by the refractive relationship

             n₁ sin θ₁ = n₂ sin θ₂

             n1 = n2 / sin θ₁

For this relationship to be fulfilled, the liquid index must be greater than the air index divided by the sine of the critical angle

Let's use trigonometry to find angle

               tan θ = y / x

                θ = tan⁻¹ 7.2 / 8.6

                θ = 39.94º

         

                n₁ = 1 / sin 39.94

                n = 1.56

This is the refractive index of the liquid

4 0
3 years ago
The chemical equation below shows the reaction of methane (CH4) and oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O)
Nuetrik [128]
<h2>Answer </h2>

Option C - Carbon Dioxide and Water

<u>Explanation </u>

The chemical equation reaction of methane (CH4) and oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O).

CH4 + 2O2 → CO2 + 2H2O.

In this equation, carbon dioxide and water are products. Products are substances which are formed after a chemical reaction so in this case carbon dioxide and water are formed as a result after a chemical reaction. Therefore, these are products of reaction of methane and oxygen gas.

8 0
3 years ago
Read 2 more answers
How is an electromagnet different from a bar magnet?
Umnica [9.8K]

Answer:

The answer should be C

Explanation:

The reason for that is because electromagnet needs electricity to start attracting anything at all but it's attracting power is also stronger because of it

Warning: This may or may not be a completely correct answer, hope you compare answer and don't blindly trust my answer

6 0
3 years ago
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