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Kaylis [27]
3 years ago
7

The law of repulsion by Coulomb agrees with:

Physics
2 answers:
r-ruslan [8.4K]3 years ago
8 0
<span>In Coulomb's law, however, the magnitude and sign of the electric force are determined by the electric charge, rather than the mass, of an object. ... Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges</span>
goblinko [34]3 years ago
5 0

Answer & explanation:

Coulomb's law refers to the forces of interaction (attraction and repulsion) between two punctual electrical charges, that is, with negligible size and mass.

According to the principle of attraction and repulsion, charges with opposite signs are attracted and with equal signs are repelled, but these interaction forces have equal intensity, regardless of the direction in which the vector describing them points.  

Through laboratory measurements, Coulomb determined that the value of the modulus of force that exists between two charged spheres, one charge (Q1) and another charge (Q2), is proportional to the product, in modulus, of its loads and inversely proportional to the square of the charge in a distance d between them. This can be described in the following equation:

F = k * (|Q1| * |Q2|) / d^2

Where F is the force between the charges, Q₁ and Q₂ being the modulus of the charges of the spheres and d is the distance between them, while k is called the electrostatic constant.

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Determine the amount of work done by the applied force when a 87 N force is applied to move a 15 kg object a horizontal
elena-s [515]

Answer:

391.5 J

Explanation:

The amount of work done can be calculated using the formula:

  • W = F║d
  • where the force is parallel to the displacement

Looking at the formula, we can see that the mass of the object does not affect the work done on it.

Substitute the force applied and the displacement of the object into the equation.

  • W = (87 N)(4.5 m)
  • W = 391.5 J  

The amount of work done on the object is 391.5 J in order to move it 4.5 meters with an applied force of 87 Newtons.

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2 years ago
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If the student hit a drum in his bedroom how would the sound wave behave differently than if he hit it in a swimming pool? Pleas
zlopas [31]
The sound wave would behave differently in a swimming pool than in his bedroom because sound waves travel faster in more dense mediums; such as water. The wave will travel faster in water, and slower in air.
4 0
3 years ago
What is the action force and the reaction force when you sit down on a chair
Harlamova29_29 [7]
Your weight pushing down on the chair is the action force. The reaction force is the force exerted by the chair that pushes up on your body.
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3 years ago
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Which term describes the difference in electrical charge across a membrane? View Available Hint(s) Which term describes the diff
Zinaida [17]

Answer:

Membrane potential

Explanation:

Membrane potential is describes the difference in electrical charge across a membrane.                                                                                                              

The difference in potential between exterior  and  interior of the  biological cell is known as Membrane potential.Generally it is denoted by  millivolts like mV and varies from -80 V to -40 V.

So the answer is Membrane potential

4 0
3 years ago
A billiard ball of mass m moving with speed v1=1 m/s collides head-on with a second ball of mass 2m which is at rest. What is th
Soloha48 [4]

Answer:

The velocity of mass 2m is  v_B = 0.67 m/s

Explanation:

From the question w are told that

     The mass of the billiard ball A is =m

     The initial speed  of the billiard ball A = v_1 =1 m/s

    The mass of the billiard ball B is = 2 m

    The initial speed  of the billiard ball  B = 0

Let the final speed  of the billiard ball A  = v_A

Let The finial speed  of the billiard ball  B = v_B

      According to the law of conservation of Energy

                 \frac{1}{2} m (v_1)^2 + \frac{1}{2} 2m (0) ^ 2 = \frac{1}{2} m (v_A)^2 + \frac{1}{2} 2m (v_B)^2

              Substituting values  

                \frac{1}{2} m (1)^2  = \frac{1}{2} m (v_A)^2 + \frac{1}{2} 2m (v_B)^2

Multiplying through by \frac{1}{2}m

                1 =v_A^2 + 2 v_B ^2 ---(1)

    According to the law of conservation of Momentum

            mv_1 + 2m(0) = mv_A + 2m v_B

    Substituting values

            m(1)  = mv_A + 2mv_B

Multiplying through by m

           1 = v_A + 2v_B ---(2)

making v_A subject of the equation 2

            v_A = 1 - 2v_B

Substituting this into equation 1

         (1 -2v_B)^2 + 2v_B^2 = 1

         1 - 4v_B + 4v_B^2 + 2v_B^2 =1

          6v_B^2  -4v_B +1 =1

          6v_B^2 -4v_B =0

Multiplying through by \frac{1}{v_B}

          6v_B -4 = 0

            v_B = \frac{4}{6}

            v_B = 0.67 m/s

4 0
3 years ago
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