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Kaylis [27]
4 years ago
7

The law of repulsion by Coulomb agrees with:

Physics
2 answers:
r-ruslan [8.4K]4 years ago
8 0
<span>In Coulomb's law, however, the magnitude and sign of the electric force are determined by the electric charge, rather than the mass, of an object. ... Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges</span>
goblinko [34]4 years ago
5 0

Answer & explanation:

Coulomb's law refers to the forces of interaction (attraction and repulsion) between two punctual electrical charges, that is, with negligible size and mass.

According to the principle of attraction and repulsion, charges with opposite signs are attracted and with equal signs are repelled, but these interaction forces have equal intensity, regardless of the direction in which the vector describing them points.  

Through laboratory measurements, Coulomb determined that the value of the modulus of force that exists between two charged spheres, one charge (Q1) and another charge (Q2), is proportional to the product, in modulus, of its loads and inversely proportional to the square of the charge in a distance d between them. This can be described in the following equation:

F = k * (|Q1| * |Q2|) / d^2

Where F is the force between the charges, Q₁ and Q₂ being the modulus of the charges of the spheres and d is the distance between them, while k is called the electrostatic constant.

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Answer:

the ball is travelling very fast and the player can get injured if he doesn't wear gloves

Explanation:

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olganol [36]

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4 0
3 years ago
A student has a displacement of 739 m north in 162 s. What was the student’s average velocity?A. 0.22 m/sB. 119,718 m/sC. 162 m/
user100 [1]

Answer:

answer below

Explanation:

Displacement of the student is 739 m due North and it takes 162 s.

We need to find the student's average velocity. Using formula of velocity.

Velocity = displacement/time

v= 739/162

v= 4.56

4 0
3 years ago
Sometimes a person cannot clearly see objects close up or far away. To correct this type of vision, bifocals are often used. The
Rudik [331]

Answer:

1)   P₁ = -2 D,   2) P₂ = 6 D

Explanation:

for this exercise in geometric optics let's use the equation of the constructor

          \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distance to the object and the image, respectively

1) to see a distant object it must be at infinity (p = ∞)

          \frac{1}{f_1} = \frac{1}{q}

           q = f₁

2) for an object located at p = 25 cm

            \frac{1}{f_2} = \frac{1}{25} + \frac{1}{q}

We can that in the two expressions we have the distance to the image, this is the distance where it can be seen clearly in general for a normal person is q = 50 cm

we substitute in the equations

1) f₁ = -50 cm

2)  

        \frac{1}{f_2} = \frac{1}{25} + \frac{1}{50}

        \frac{1}{f_2} = 0.06

         f₂ = 16.67 cm

the expression for the power of the lenses is

          P = \frac{1}{f}

where the focal length is in meters

           

1)       P₁ = 1/0.50

        P₁ = -2 D

2)     P₂ = 1 /0.16667

        P₂ = 6 D

4 0
3 years ago
A helicopter blade spins at exactly 110 revolutions per minute. Its tip is 4.50 m from the center of rotation. (a) Calculate th
NeX [460]

Answer:

(a). The average speed is 51.83 m/s.

(b). The average velocity over one revolution is zero.

Explanation:

Given that,

Angular velocity = 110 rev/m

Radius = 4.50 m

(a). We need to calculate the average speed

Using formula of average speed

v=r\omega

v = 4.50\times110\times\dfrac{2\pi}{60}

v=51.83\ m/s

(b). The average velocity over one revolution is zero because the net displacement is zero in one revolution.

Hence, (a). The average speed is 51.83 m/s.

(b). The average velocity over one revolution is zero.

8 0
3 years ago
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