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Elina [12.6K]
3 years ago
9

7/8 = x/48 A. 42 B. 6 C. 13 D. 1

Mathematics
2 answers:
Elena L [17]3 years ago
5 0
7/8 = x/48

Perform cross multiplication:
a/b = c/d
ad = bc

a = 7 ; b = 8 ; c = x ; d = 48
7*48 = 8x
336 = 8x
336/8 = x
42 = x

7/8 = 42/48

42 ÷ 6 = 7
48 ÷ 6 = 8


Viefleur [7K]3 years ago
5 0
If you would like to solve the equation 7/8 = x/48, you can calculate this using the following steps:

7/8 = x/48
     /*48
x = 7/8 * 48
x = 42

The correct result would be A. 42.
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Sunny_sXe [5.5K]

Answer:

r/c  

Step-by-step explanation:

96/48

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24/12

6 0
3 years ago
Find the volume of the oblique prism
Sergio039 [100]
Volume = 12 * area of triangular base

area of triangle = 1/2 base * height = 3 * height
                        height = sqrt(5^2 - 3^2)  = 4

area of triangle = 4*3 = 12

Vol  of prism = 12*12 = 144  cubic units
8 0
3 years ago
A ball moves in a straight line has an acceleration of a(t) = 2t + 5. Find the position function of the ball if its initial velo
Vlad1618 [11]

Answer:

s(t) = frac{t^3}{3} + \frac{5t^2}{2} - 3t + 12

Step-by-step explanation:

Relation between acceleration, velocity and position:

The velocity function is the integral of the acceleration function.

The position function is the integral of the velocity function.

Acceleration:

As given by the problem, the acceleration function is a(t) = 2t + 5

Velocity:

v(t) = \int a(t) dt = \int (2t+5) dt = \frac{2t^2}{2} + 5t + K = t^2 + 5t + K

In which K is the constant of integration, which is the initial velocity. So K = -3 and:

v(t) = t^2 + 5t - 3

Position:

s(t) = \int v(t) dt = \int (t^2 + 5t - 3) = \frac{t^3}{3} + \frac{5t^2}{2} - 3t + K

In which K, the constant of integration, is the initial position. Since it is 12:

s(t) = frac{t^3}{3} + \frac{5t^2}{2} - 3t + 12

4 0
3 years ago
The Northwest High School senior class decided to host a raffle to raise money for their senior trip. They charged $2 for each s
prisoha [69]
Let x be the tickets that the adults bought, andy be the tickets that children bought.
From the problem we have the system of linear equations:
\left \{ {{2x+5y=2686} \atop {y=3x}} \right.

The first thing we are going to do to solve our system, is replacing equation (2) in equation (1), and  then, solve for x
2x+5y=2686
2x+5(3x)=2686
2x+15x=2686
17x=2686
x= \frac{2686}{17}
x=158

Now that we have the number of tickets that the adults bought, lets replace that value in equation (2):
y=3x
y=3(158)
y=474

Last but not least, to find the total number of tickets, we are going to add x and y:
158+474=632

We can conclude that <span>Northwest High School's senior class sold 632 raffle tickets.</span>
7 0
3 years ago
Read 2 more answers
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Themes in if you were coming in the fall
8 0
3 years ago
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