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Naddika [18.5K]
3 years ago
6

Para ir a visitar a los abuelos Paula y Mario se ponen de acuerdo en que Paula vaya cada 5 días y Mario cada 6 días. Si coincidi

eron el 24 de diciembre,
a) ¿Cuándo volvieron a coincidir?

b) ¿Cuántas visitas habrá hecho cada uno?
Mathematics
1 answer:
photoshop1234 [79]3 years ago
4 0

Answer:

a) January 24(24 de Enero)

b) Paula will have made 5 visits(Paula habrá hecho 5 visitas). Mario will have made 4 visits(Mario habrá hecho 4 visitas).

Step-by-step explanation:

When two events, A and B, happen every x and y days, respectively, they will happen on the same day in each lcm(x,y) days. lcm(x,y) is the lesser common multiple of x and y which is not 0.

In this question:

Paula each 5 days

Mario each 6 days

Multiples of 5: {0, 5, 10, 15, 20,25,30, ...}

Multiples of 6: {0, 6, 12, 18, 24, 30, ...}

a) ¿Cuándo volvieron a coincidir?

lcm(5,6) = 30

30 days from December 24, which is January 24(24 de Enero).

b) ¿Cuántas visitas habrá hecho cada uno?

Paula visits each 5 days.

30 is 6th non-zero multiple of 5. This means that on January 24 will be her 6th visit. So she will have made 5 visits.

30 is the 5th non-zero multiple of 6. This means that on January 24 will be her 5th visit. So he will have made 4 visits.

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The sum of two numbers is -26. One number is 148 less than the other. Find the numbers
maks197457 [2]

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61 and -87

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3 years ago
carlos can write 3 to 4 pages in his journal in 2/3 hour. if he writes for 5 hours, what's a reasonable number of pages he can w
zheka24 [161]

Answer:

23, 24, 25, 26, 27, 28, 29, or 30

22.5 ≤ p ≤ 30

Step-by-step explanation:

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First, lets find how many 2/3's are in 5. Lets divide 5 by 2/3.

\frac{5}{\frac{2}{3}}=7.5

So there are 7.5 2/3's in 5.

Now, lets assume Carlos writes 4 pages per 2/3 hours consistently throughout that 5 hours. This would yield the maximum amount of pages Carlos can write in 5 hours.

7.5(4) = 30

So the maximum amount of pages Carlos can write in 5 hours is 30.

Now, lets assume Carlos writes 3 pages per 2/3 hours consistently throughout that 5 hours. This would yield the minimum amount of pages Carlos can write in 5 hours.

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So the minimum amount of pages Carlos can write in 5 hours is 22.5.

Now we can write the information that we found as an inequality. Lets make p equal to the pages that Carlos can write in 5 hours.

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Answer:

aₙ = -15 + 10 * (n-1)

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d = 10

a₁ = -15

Formula: aₙ = -15 + 10 * (n-1)

8 0
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