Question

Two points in a rectangular coordinate system have the coordinates (5.5, 2.9) and (−3.5, 4.8), where the units are centimeters. Determine the distance between these points.

Answer 1

Answer:

The distance between these points is approximately is 9.198 units.

Step-by-step explanation:

Let be (5.5, 2.9) and (-3.5, 4.8) the location of the points in Cartesian plane. The straight line distance between both points ($d$) is determined by the Pythagorean Theorem, which is described below:

$d = \sqrt{(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2}}$

Where:

$x_{A}$, $x_{B}$ - Horizontal components of each point, dimensionless.

$y_{A}$, $y_{B}$ - Vertical components of each point, dimensionless.

If $A = (5.5, 2.9)$ and $B = (-3.5,4.8)$, the distance between these points is:

$d = \sqrt{(-3.5-5.5)^{2}+(4.8-2.9)^{2}}$

$d\approx 9.198$

The distance between these points is approximately is 9.198 units.