Each time the frog population increases, they’re swamp will be decreasing. Resulting in lack of food due to too much frogs in one swamp.
Options have not been provided for the question. They are as follows:
What is the correct order for these genes using a linkage map analysis?
A. Z-X-Y-W
B. X-W-Z-Y
C. W-X-Y-Z
D. Y-W-Z-X
E. Z-X-W-Y
F. Y-X-W-Z
Between which two genes is crossing over most likely to occur?
A. B and D
B.X and Z
C. X and W
D. X and Y
E. W and Z
F. Y and W
G.Y and Z
Answer:
Correct order for these genes using a linkage map analysis: E. Z-X-W-Y
Two genes between which the crossover is most likely to occur: G.Y and Z
Explanation:
According to linkage concept, recombination frequency between two genes = distance between two genes in cM
Here, smallest distance is between X and W ( 7cM ) so they are present next to each other. Distance between X and Y is 17cM and between W and Y is 10cM so W is present between X and Y. Distance between X and Z is 13 cM. Since on one side of X, W and Y are already present Z lies on the other side. So, the final gene order comes out to be, Z-X-W-Y.
According to the gene order, Y and Z genes are farthest from each other. Chances of crossover or recombination increases with increasing distance between genes. So, Y and Z have the highest probability to show crossing over.
I think the answer is transfer RNA
There are specific methods to be used when measuring the rate of diffusion over a membrane.
In order to accurately measure the rate of diffusion for water through this permeable membrane you need to account for:
- The difference in pressure
- The surface area of the membrane
- The diffusion barrier
It would be correct to state that the speed at which any movement of water occurs is dependent on the pressure being exerted onto the water. This means that when attempting to calculate the rate of diffusion we need to account for the pressure difference. This pressure will be caused by the osmotic gradient.
You will also need to account for the surface area of the membrane and the diffusion barrier. The <u>surface area </u>of the membrane allows us to understand how much <u>space </u>the water has to be able to move from one side to the other. Meanwhile, the <u>diffusion barrier </u>tells us how much <u>resistance </u>the water will have to overcome when diffusing.
By taking all of these parameters into account, we can then use Fick's law to accurately calculate the rate of diffusion for the water and therefore the amount of water that is diffusing through the membrane.
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Answer:
They would be smaller than their normal size.
Explanation:
The G2 phase of a cell's cycle is where the cell starts preparing itself for the mitosis by producing proteins and growing in size. If the G2 phase of the parent cell is shortened, then the cell is not able to grow as much as it needs but this does not affect the mitosis process, the daughter cells would be much smaller due to the parent cell's size.
I hope this answer helps.
