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FinnZ [79.3K]
3 years ago
5

Write an equation of lines whose graph is parallel to the graph of y=3x-10

Mathematics
1 answer:
katrin [286]3 years ago
7 0
Parallel lines have the same slope.

So the graph of  [ y = 3x + any number ] is parallel
to the graph of  [ y = 3x - 10 ] .
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△ABCis reflected to form​​ ​△A′B′C′​. The vertices of △ABC are A(3, 1), B(1, 5), and C(6, 9). The vertices of △A′B′C′ are A′(−1,
Blababa [14]

Answer:  D) reflection across y = -x

Explanation:

When we reflect over y = x, we basically swap x and y. So for instance, the point (3,1) becomes (1,3).

When reflecting over y = -x, we will do the same thing but we'll make each coordinate swap in sign from positive to negative (or vice versa). The rule for reflecting over y = -x is (x,y) \to (-y,-x)

So if we apply that rule to point A(3,1) then it becomes A ' (-1, -3).

Similarly, B(1,5) moves to B ' (-5, -1)

Finally, C(6,9) becomes C ' (-9, -6)

5 0
2 years ago
The radius of a circle is 13miles. what is the area of a sector bounded by a 20 degree arc
Stolb23 [73]

Answer:

Area of the sector = 29.48 square miles.

Step-by-step explanation:

Given:

Radius of a circle = 13 miles

Angle bounded by the arc = 20 deg

To find

Area of the sector bounded by 20 degrees.

Note: Area of a sector = \frac{(\theta)}{360}\times \pi\times r^2

Plugging the values in the equation.

⇒ \frac{(\theta)}{360}\times \pi\times r^2

⇒ (\frac{20}{360})\times  3.14\times 13^2

⇒ 29.48 square-miles

So the area of the sector bounded by 20 degree arc is 29.48 square miles.

5 0
3 years ago
The perimeter of a rectangular painting is 310 centimeters. If the width of the painting is 56 centim
gtnhenbr [62]

Answer:

The length is 99 cm

Step-by-step explanation:

The perimeter of a rectangle is

P = 2 (l+w)

310 = 2( l+56)

Divide each side by 2

310/2 = 2/2( l+56)

155 = l+56

Subtract 56

155-56 = l+56-56

99 = l

7 0
2 years ago
Read 2 more answers
Please help me out I need it done ASAP
irinina [24]
Your answer will be letter c
7 0
3 years ago
Write a simplified polynomial expression in standard form to represent the area of the rectangle below.
Burka [1]
Area of Rectangle = length times width
lets say length = 2x-4
width = x+5

Note: you can switch these around, width could be 2x-4 and length could be x+5, it doesnt matter.

With that being said:
length * width = area
(2x-4)(x+5)=area
FOIL (First Outer Inner Last)
2x^{2}+10x-4x-20=area
Simplify:
x^{2}+6x-20=area
3 0
3 years ago
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