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Colt1911 [192]
3 years ago
6

(a) An angle measures 25°. What is the measure of its complement?

Mathematics
1 answer:
Setler79 [48]3 years ago
5 0

Answer:

A) 65 degrees

B) 89 degrees

Step-by-step explanation:

Complementary angles always add up to 90 degrees whereas supplementary angles always add up to 180 degrees

Hope it helps :)

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Which of the following functions represent exponential decay?
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Option C: $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$ is the function that represent exponential decay.

Explanation:

The exponential decay can be represented by

$f(x)=a \cdot b^{x}$ where a>0 and 0

Option A: $f(x)=3(1.7)^{x-2}$

From the function, we can see that a=3 and b=1.7

Thus, a>0 and b>1

Thus, the function $f(x)=3(1.7)^{x-2}$ does not represent exponential decay.

Hence, Option A is not the correct answer.

Option B: $f(x)=3(1.7)^{-2 x}$

From the function, we can see that a=3 and b=1.7

Thus, a>0 and b>1

Thus, the function $f(x)=3(1.7)^{-2 x}$ does not represent exponential decay.

Hence, Option B is not the correct answer.

Option C: $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$

From the function, we can see that a=3^5=243 and b=\frac{1}{3} =0.3333

Thus, a>0 and 0

Thus, the function $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$ represent exponential decay.

Hence, Option C is the correct answer.

Option D: $f(x)=3^{5}(2)^{-x}$

From the function, we can see that a=3^5=243 and b=2

Thus, a>0 and b>1

Thus, the function $f(x)=3^{5}(2)^{-x}$ does not represent exponential decay.

Hence, Option D is not the correct answer.

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