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Artyom0805 [142]
3 years ago
14

Identify cosQ as a fraction and as a decimal rounded to the nearest hundredth. HELP ASAP! PLEASE!!

Mathematics
1 answer:
cluponka [151]3 years ago
7 0

Answer:

Step-by-step explanation:

Cos(Q) = adjacent to Q/Hypotenuse

adjacent = 15

Hypotenuse = 17.7

Cos(Q) = 15/17.7

Cos(Q) = 0.8475

The answer is C.

D is impossible. The cos of any angle can never be more than 1.

B is  Tan(Q). They are not the same.

A is  Sin(Q)

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Take the derivative to get

\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k

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Take the derivative again:

\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k

Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

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so we have

\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

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