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cluponka [151]
3 years ago
13

which equations are equivalent to 3/4+m=-7/4 check all that apply m=10/4 m=-10/4 m=-5/2 11/4+m=-1/4 -5/4+m=-15/4 m+2=-0.5 Help f

ast!!!!!!!!
Mathematics
2 answers:
laiz [17]3 years ago
6 0

Answer:

m=-\frac{10}{4}

m=-\frac{5}{2}

-\frac{5}{4}+m=-\frac{15}{4}

m+2=-0.5

Step-by-step explanation:

Given equation,

\frac{3}{4}+m=-\frac{7}{4}

\implies m = -\frac{7}{4}-\frac{3}{4}=\frac{-7-3}{4}=-\frac{10}{4}=-\frac{5}{2},

Since, \frac{10}{4}\neq -\frac{5}{2}

\frac{11}{4}+m = -\frac{1}{4}

\implies m = -\frac{1}{4}-\frac{11}{4}=\frac{-1-11}{4}=-\frac{12}{4}=-3\neq -\frac{5}{2}

-\frac{5}{4}+m=-\frac{15}{4}\implies m = -\frac{15}{4}+\frac{5}{4}=\frac{-15+5}{4}=-\frac{10}{4}

m+2=-0.5\implies m = -0.5-2\implies m = -2.5=-\frac{5}{2}

Alecsey [184]3 years ago
3 0

Answer:

The correct choices are; B,C,E, and F.

Step-by-step explanation:

The given equation is;

\frac{3}{4}+m=-\frac{7}{4}

We solve for m to obtain:

m=-\frac{7}{4}-\frac{3}{4}=-2.5

We also solve the remaining equations to see which ones give the same result.

A: m=\frac{10}{4} =2.5

B:m=-\frac{10}{4} =-2.5

C:m=-\frac{5}{2} =-2.5

D: \frac{11}{4}+m=-\frac{1}{4}

m=-\frac{1}{4}-\frac{11}{4}=-3

E: -\frac{5}{4}+m=-\frac{15}{4}

m=-\frac{15}{4}+\frac{5}{4}=-2.5

F: m+2=-0.5

m=-0.5-2=-2.5

The equivalent equations are; B,C,E, and F.

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Answer:

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Step-by-step explanation:

The given geometric sequence is

2, 8, 32, 128,....

The general form of a geometric sequence is given by

a_{n} = a_{1}\cdot r^{n-1}

Where n is the nth term that we want to find out.

a₁ is the first term in the geometric sequence that is 2

r is the common ratio and can found by simply dividing any two consecutive numbers in the sequence,

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You can try other consecutive numbers too, you will get the same common ratio

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So the common ratio is 4 in this case.

Substitute the value of a₁ and r into the above general equation

a_{n} = 2\cdot 4^{n-1}

This is the general form of the given geometric sequence.

Therefore, the correct option is B

Note: Don't multiply the first term and common ratio otherwise you wont get correct results.

Verification:

a_{n} = 2\cdot 4^{n-1}

Lets find out the 2nd term

Substitute n = 2

a_{2} = 2\cdot 4^{2-1} = 2\cdot 4^{1} = 2\cdot 4 = 8

Lets find out the 3rd term

Substitute n = 3

a_{3} = 2\cdot 4^{3-1} = 2\cdot 4^{2} = 2\cdot 16 = 32

Lets find out the 4th term

Substitute n = 4

a_{4} = 2\cdot 4^{4-1} = 2\cdot 4^{3} = 2\cdot 64 = 128

Lets find out the 5th term

Substitute n = 5

a_{5} = 2\cdot 4^{5-1} = 2\cdot 4^{4} = 2\cdot 256 = 512

Hence, we are getting correct results!

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Step-by-step explanation:

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