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alexandr1967 [171]
3 years ago
10

Which of the following values are in the range of the function graphed below? check all that apply

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
6 0
I think the answer is A
jasenka [17]3 years ago
4 0

Answer:

A: -1

Step-by-step explanation:

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Simplify 27^2.<br><br> please (thxx)
adoni [48]

Answer:

729

Step-by-step explanation:

Raise 27 to the power of 2.

729

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3 years ago
PLEASE PLEASE HELP ME ASAPPP
Ivenika [448]

Answer:

a. <u><em>14:45pm</em></u> (It's really easy to convert to a 24-hour clock time, all you need to do is add 12 hours onto the hour. Eg. 2 + 12 = 14 so it will be 14:45.pm

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Hope that helps. x

8 0
2 years ago
Using the greatest common factor for the terms, how can you write 56 + 32 as a product?
11Alexandr11 [23.1K]
56 + 32 = (8 x 7) + (8 x 4) = 8(7 + 4) (Answer C)


6 0
3 years ago
Please help i dont remember how to do this
inessss [21]
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8 0
2 years ago
The temperature at a point (x, y) is T(x, y), measured in degrees Celsius. A bug crawls so that its position after t seconds is
aniked [119]

Answer:

10.50°C

Step-by-step explanation:

Given x = 2 + t , y = 1 + 1/2t where x and y are measured in centimeters. Also, the temperature function satisfies Tx(2, 2) = 9 and Ty(2, 2) = 3

The rate of change in temperature of the bug path can be expressed using the composite formula:

dT/dt = Tx(dx/dt) + Ty(dy/dt)

If x = 2+t; dx/dt = 1

If y = 1+12t; dy/dt = 1/2

Substituting the parameters gotten into dT/dt we will have;

dT/dt = 9(1)+3(1/2)

dT/dt = 9+1.5

dT/dt = 10.50°C/s

Hence the rate at which the temperature is rising along the bug's path is 10.50°C/s

7 0
3 years ago
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