Answer:
Step-by-step explanation:
so llets find what 15% of 60% really is,
0.15*0.60=0.09
0.09 AKA 9%
so since 9% of people didn't show up we can subtract 9% from 60%
so 60-9=51
51% of setas are taken
to find the percent of seats still empty, subtract 100 form 51
so
100-51=49
49% of seats are still empty
Hope this helsp!
Answer:
she messed up on step two because she has to subtract 10 from both sides
Step-by-step explanation:
step 1: -6(x+3)+10<-2
step2:-6(x+3)+10-10<-2-10
step3: -6(x+3)<-12
step4: (-6)(x+3)(-1)≥(-12)(-1)
step5:6(x+3)>12
step6:divide both sides by 6
step7:simplify and subtract 3 from both sides and then simplify again
The answer to the problem wherein a computer simulation tossed a 10-faced die 5 times and you have to compute for the possible outcomes is simple. The answer is <span>18,144, 000 possible outcomes (if it's a combination). I got this through simply getting the 10! (3,628,800) and multiplying it 5.
However, if order is important (permutation), the number of possible outcomes is is </span>30240.
If this is algebra, then you will be using a parabola to solve this problem:
t=-b/2a
t=-8/2(-16) = 8/-32 = -1/4
t=-1/4=-0.25
h=-16(0.0625)+8(-0.25)+80
h=1-2+80
h=79
(-0.25,79)
then plug this ordered pair above and draw a line directly down the middle of it to use as a "mirror" and plug 2 different numbers(preferably 0 and 1) into the variable t to find the other two points and then reflect the two points over the "mirror" to get the last two points to graph your paprabola
