1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Afina-wow [57]
3 years ago
11

Using the Peng-Robinson equation of state, calculate the work needed in (kJ/mol) for a steady-state flow reversible adiabatic co

mpression of gaseous FREON-12, a refrigerant, from a pressure of 0.75 MPa and temperature of 325 K to a pressure of 2 MPa.

Physics
1 answer:
trasher [3.6K]3 years ago
3 0

Answer:

3.059 KJ/mole

Explanation:

check the picture attached for explanation

You might be interested in
A force of 8 N is used to drag a chair 2.5 metres across a room. Calculate the work done to move the chair.
NNADVOKAT [17]

Answer:

Explanation:

GIVEN

Force (F) = 8 N

Distance (d) = 2.5 metres

Work done = ?

WE know we have the formula

work done = F * d

Work done = 8 * 2.5

                   = 20 Joule

Hope it helps :)

8 0
4 years ago
Read 2 more answers
20 points, just need a basic understanding. You are on a mystery planet, what you know is that from a height of 10.0 meters, a d
ICE Princess25 [194]

(since you asked for basic understanding only, I am not including actual calculations. Please let me know in the comments section if you wish to verify your solution(s))

For (b): Use the formula for distance (s) made during an accelerated motion:

s = \frac{1}{2}at^2+ v_0t+s_0= \frac{1}{2}at^2= \frac{1}{2}gt^2

with v_0 and s_0 being the initial velocity and distance, both 0 in this case, and with "a" denoting the acceleration, in this case  solely due to gravitational acceleration so: "g."

You are given the distance made, namely 10 m, and the duration t (0.88s) and so using the formula above you can solve for g.

For (c), to determine the final velocity at time 0.88s use the formula for the instantaneous velocity of an accelerated motion

(velocity at time t) = (acceleration) x (time)  

again, with acceleration due to gravity, i.e., a = g and with g as determined under (b).  

If my calculation is correct, this mystery planet could be the Jupiter.


7 0
4 years ago
What is the mass of erath
Wittaler [7]
  1. the earth mass is clicked as a picture at up

6 0
4 years ago
Suppose Gabor, a scuba diver, is at a depth of 15m. Assume that: The air pressure in his air tract is the same as the net water
s2008m [1.1K]

Complete Question

The complete question is shown on the first and second uploaded image

Answer:

a

Now the ratio of the gases in Gabor's lungs at the depth of 15m to that at

the surface is \frac{(n/V)_{15\ m}}{(n/V)_{surface}} = 2.5

b

The number of moles of gas that must be released is  n= 0.3538\ mols

Explanation:

We are told from the question that the pressure at the surface is 1 atm and for each depth of 10m below the surface the pressure increase by 1 atm

 This means that the pressure at the depth of the surface would be

                P_d = [\frac{15m}{10m} ] (1 atm) + 1 atm

                      = 2.5 atm

The ideal gas equation is mathematically represented as

                PV = nRT

Where P is pressure at the surface

           V is the volume

            R is the gas constant  = 8.314 J/mol. K

making n the subject we have

        n = \frac{PV}{RT}

 Considering at the surface of the water the number of moles at the surface would be

               n_s = \frac{P_sV}{RT}

Substituting 1 atm = 101325 N/m^2 for P_s ,6L = 6*10^{-3}m^3 for volume , 8.314 J/mol. K for R , (37° +273) K for T into the equation

              n_s = \frac{(1atm)(6*10^{-3} m^3)}{(8.314J/mol \cdot K)(37 +273)K}

                   = 0.2359 mol  

To obtain the number of moles at the depth of the water we use

                n_d  = \frac{P_d V}{RT}

Where P_d \ and \ n_d \ are pressure and no of moles at the depth of the water

        Substituting values we have

              n_d = \frac{(2.5)(101325 N/m^2)(6*10^{-3}m^3)}{(8.314 J/mol \cdot K)(37 + 273)K}

                  = 0.5897 mol

Now to obtain the number of moles released we have

             n =  n_d - n_s

               = 0.5897mol  - 0.2359mol

              =0.3538 \ mol

     The molar concentration at the surface  of water is

                [\frac{n}{V} ]_{surface} = \frac{0.2359mol}{6*10^-3m^3}

                                =39.31mol/m^3

    The molar concentration at the depth  of water is

           [\frac{n}{V} ]_{15m} = \frac{0.5897}{6*10^{-3}}

                      = 98.28 mol/m^3

Now the ratio of the gases in Gabor's lungs at the depth of 15m to that at the surface is

         \frac{(n/V)_{15\ m}}{(n/V)_{surface}} = \frac{98.28}{39.31} =2.5

                   

                     

                     

6 0
3 years ago
TRUE OR FALSE. When non-conservative forces are present, the amount of work done increases with the length of the path.
Ymorist [56]

Answer:

True

Explanation:

When non-conservative forces are present, the amount of work done increases with the length of the path, this is true because, when a force is applied, the force does when and the non-conservative forces also do work. Since the non-conservative force work against the force  applied, this tend to increase the net work done by the applied force to compensate for the loss in energy due to the work done by the non-conservative forces.

6 0
3 years ago
Other questions:
  • PLEASE HELP
    7·1 answer
  • A cannonball is catapulted toward a castle. The cannonball’s velocity when it leaves the catapult is 51.6 m/s at an angle of 37.
    5·1 answer
  • Relate a car's suspension to harmonic motion
    7·2 answers
  • What is the term for the cumulative body of observations on which scientific explanations are based?
    6·1 answer
  • A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110.m. Determine the acceleration
    6·1 answer
  • What do we call the movement of electric charge?<br> A. Power B. Voltage C. Resistance D. Current
    9·2 answers
  • The instrument panel in a car usually has a display in units of kilometres or miles per hour. The displayed value tells you whic
    8·1 answer
  • A. If the object is not moving relative to the surface it's in contact with. the friction force is static friction. Draw a free-
    12·1 answer
  • Explain the difference between a high tide and a low tide.
    10·1 answer
  • Andre listed some properties of electromagnetic waves.
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!