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ElenaW [278]
3 years ago
6

A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110.m. Determine the acceleration

of the car.
Physics
1 answer:
AlexFokin [52]3 years ago
6 0
Seriously this is fun dont know why u want me to enjoy this so ummmm hmmm lolololol  the equation for this would be s=vif+1/2at^2 so time is lets see plug it and vell vi=0 since it started from rest so s=1/2at^2 and plug it in the displacement and time 110=1/2 a 5.21^2 and solve it and u get 8.1m/s^2

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In 1970, a rocket powered car called Blue Flame achieved a maximum speed of 1.00(10 km/h (278m/s).Suppose the magnitude of the c
sammy [17]

Answer:

Distance traveled during this acceleration will be 6950 m

Explanation:

Wear have given maximum speed tat will be equal to final speed of the car        v = 278 m/sec

Constant acceleration a=5.56m/sec^2

As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec

From third equation of motion v^2=u^2+2as

Putting all values in equation

278^2=0^2+2\times 5.56\times s

s = 6950 m

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kolezko [41]

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Explanation:

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a = (V² - V₀²) / (2 d) = (2.5² - 1²) / (2 · 5) = (6.25 - 1) / 10 = 5.25 / 10

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then we use this formula

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God is with you!!!

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Its B i got it right on the test
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