Question

Which shows the equation below written in standard form?

Answer 1

$9-7x=(4x-3)^2+5 \\ 9-7x=16x^2-24x+9+5 \\ 9-7x=16x^2-24x+14 \\ 0=16x^2-24x+14-9+7x \\ 0=16x^2-17x+5 \\ \boxed{16x^2-17x+5=0} \\ \hbox{answer D}$

Answer 2

Answer:

Option D - $16x^2-17x + 5=0$

Step-by-step explanation:

Given : Expression $9 - 7x = (4x - 3)^2 + 5$

To find : Which shows the equation below written in standard form?

Solution :

Step 1 - Write the expression

$9 - 7x = (4x - 3)^2 + 5$

Step 2 - Solve the square term

$9 - 7x = 16x^2+9-24x + 5$

Step 3 - Place like term together

$16x^2-24x+7x + 5+9-9=0$

$16x^2-17x + 5=0$

Therefore, Option D is correct.

The standard form of the equation is $16x^2-17x + 5=0$