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3 years ago

(3 sqrt(-4)) + (5 sqrt(-121)) =

Mathematics

1 answer:

defon3 years ago

5 0

Answer: 61i

hope it helps

Step-by-step explanation:

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X^2 + 2x + 5 find the zeros

Dvinal [7]

Answer:

Step-by-step explanation:

This is what I got

8 0

3 years ago

If you get a check for $289.25 a week, how much will you have made it at the end of the month

ankoles [38]

1,157 a month has approximate of 4 weeks so
289.25 x 4 = 1,157

4 0

3 years ago

Read 2 more answers

Solve each quadratic equation. Show your work.

umka2103 [35]

14. 2x-1 = 0, x+7=0
x = 1/2, x = -7

15. x^2 + 3x - 10 = 0
(x + 5)(x - 2) = 0
x = -5, x = 2

16. x^2 - 25 = 0
(x-5)(x+5)
x = 5, x = -5

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4 years ago

factor 3a^5-18a^3+6a^2, I know the answer is 3a^2(a^3-6a+2) but I am so lost on how to get the factor of 3a^2..How in the world

rusak2 [61]

Answer:

$\huge\boxed{3a^2(a^3-6a+2)}$

Step-by-step explanation:

$\sf 3a^5-18a^3+6a^2\\\\HCF = 3a^2\\\\Take \ 3a^2 \ common\\\\= 3a^2(a^3-6a+2)\\\\\rule[225]{225}{2}$

Hope this helped!

5 0

3 years ago

What is the dimension of a rectangle if the perimeter is 198

AfilCa [17]

Answer:

Length = 49.5 unit and width = 49.5 unit

Step-by-step explanation:

Given as , Perimeter of rectangle = 198 unit

so ,as Perimeter of rectangle = 2× ( Length + width)

Or, 198 = 2 × (Length + width)

Or, $\frac{198}{2}$ = length + width

So, length + width = 99 unit

Now to make area maximum

Length × width = maximum

Or, (99 - width ) × width = maximum

99 Width - width² = maximum Let width = W

Now differentiate both side with respect to W

D(99W - W²) $\frac{D(99w - w^2)}{Dw}$ = 0 as, constant diff is 0

So, 99 - 2w = 0

Or, w = $\frac{99}{2}$

Or, w = 49.5 unit and L = 99- 4905 = 49.5 unit Answer

3 0

4 years ago