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Goryan [66]
3 years ago
9

¾ is considered a real and rational number. true or false?

Mathematics
2 answers:
allsm [11]3 years ago
8 0
True. 3/4 is both a real and rational number
allochka39001 [22]3 years ago
3 0
IT is True. 
<span>¾ is considered a  real number</span>
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Please help me ive been stuck on this question for days! Thank you
Zielflug [23.3K]
Okay, so this is basically telling you that there is no solution. You don't have to worry about there being one. You just have to justify (or explain) why there isn't one.

Basically, neither y or x is equal to anything. You couldn't make x equal to a value in y because x and y are both together in the equation and equal to numbers. 

We can always move a factor to the other side. So,

x-2y= -8

Add 2y to the other side.

x= -8+2y

Now, plug in -8+2y as x.

3(-8+2y)- 6y=-12

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The 6y's cancel out. So, we can't figure out what y is.

-24=-12 <- no y.

These two lines are 
parallel. They have direct proportion in each other. That is why there is no solution because the lines never cross. Parallel lines do not cross. 

I hope this helps! 
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Help now!! A triangle with side measurements 10, 24 and 26 is a right triangle.
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Answer:

50

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

over the interval [-1,1], f(x) is greater than 0

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30 POINTS PLEASE HELP!!! 4. The following equations represent the same quadratic function written in standard, vertex, and inter
sergij07 [2.7K]

Answer:

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Step-by-step explanation:

So we have the quadratic equation and it's written in three equivalent forms:

f(x)=0.5x^2+x-1.5\\f(x)=0.5(x+1)^2-2\\f(x)=(0.5x+1.5)(x-1)

Let's determine the characteristics of the quadratic equation with the given equations.

From the first equation, since the leading coefficient (0.5) is positive, we can be certain that the graph opens upwards.

Also, the constant term is -1.5, so the y-intercept is (0,-1.5).

The second equation is the vertex form. Vertex form has the format:

f(x)=a(x-h)^2-k

Where (h,k) is the vertex. From the second equation we know that h is -1 (because (x+1) is the same as (x-(-1))) and k is -2. Therefore, the vertex is (-1,-2).

And since the graph points upwards, this means that (-1,-2) is the minimum point of the function. In other words, the range of the function is greater than or equal to -2. In interval notation, this is:

[-2,\infty)

This also means that the end behavior of the graph as a x approaches negative and positive infinity is positive infinity because the graph will always go straight up.

Also, the third form is the factored form. With that, we can solve for the zeros of the quadratic. The zeros are:

0.5x+1.5=0\text{ and } x-1=0\\0.5x=-1.5 \text{ and }x=1\\x=-3\text{ and }x=1

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So, from the three equations, we gathered the following information:

1) The graph curves upwards.

2) The roots of zeros of the function is (-3,0) and (1,0).

3) The y-intercept is (0,-1.5).

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5) Therefore, the range of the graph is all values greater than or equal to -2.

6) The end behavior of the graph on both directions go towards positive infinity.

Therefore, our correct answer is A.

B is not correct because the line of symmetry (or the x-coordinate of the vertex) here is -1 and not 1/2.

C is not correct because the graph goes towards <em>positive </em>infinity since it shoots straight up.

And D is not correct because the y-intercept is (0,-1.5).

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