Answer:
The answer is B. 2/3 because y=mx+b mx us always the slope and b is the y intercept
Answer:
Option A - Neither. Lines intersect but are not perpendicular. One Solution.
Option B - Lines are equivalent. Infinitely many solutions
Option C - Lines are perpendicular. Only one solution
Option D - Lines are parallel. No solution
Step-by-step explanation:
The slope equation is known as;
y = mx + c
Where m is slope and c is intercept.
Now, two lines are parallel if their slopes are equal.
Looking at the options;
Option D with y = 12x + 6 and y = 12x - 7 have the same slope of 12.
Thus,the lines are parrallel, no solution.
Two lines are perpendicular if the product of their slopes is -1. Option C is the one that falls into this category because -2/5 × 5/2 = - 1. Thus, lines here are perpendicular and have one solution.
Two lines are said to intersect but not perpendicular if they have different slopes but their products are not -1.
Option A falls into this category because - 9 ≠ 3/2 and their product is not -1.
Two lines are said to be equivalent with infinitely many solutions when their slopes and y-intercept are equal.
Option B falls into this category.
Answer:
20% of 45 is 9,
Step-by-step explanation:
So the answer must be 9 for an example 50% of 18 is 9 because to find 50% of something simply divide by 2 .10% of 90 is 9 because to find 10% of something divide by 10. 25% of 36 is 9 because you divide by 4 to get 25% of anything.
Answer:
There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555
Step-by-step explanation:
Given the functions:
f(x) = x² + 4x + 10
g(x) = -32x - 40
we want to find the points at which f(x) = g(x).
x² + 4x + 10 = -32x - 40
x² + 4x + 10 + 32x + 40 = 0
x² + 36x + 50 = 0
Using quadratic formula:







A. Average rate of change for x=1 to 2: 4(2²)-4(2)=16-8=8; from x=3 to 4: 4(2⁴)-4(2³)=64-32=32.
b. Section b is 32/8=4 times greater. As the exponent of 2 increases, the gaps between consecutive powers of 2 gets wider and therefore the rate of change is greater.