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Amanda [17]
3 years ago
14

12=p-25 what is the value of p? Pls help

Mathematics
1 answer:
Ierofanga [76]3 years ago
7 0

STEPS:

First add 25 to both sides of the equation in order to get our variable in this case <em>p</em> isolated.

On the right -25 and +25 cancel and we have <em>p</em>. On the right, 12 + 25 gives us a sum of 37 so <em>p</em> = 37<em>.</em>

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Evaluate Ic2 + b2l, given a = 5, b = -3, and c= -2.
LenKa [72]

Answer:

Ic² + b²l = 13 units.

Step-by-step explanation:

We have to evaluate the expression Ic² + b²l with unknowns b and c and having the values of b and c respectively - 3 and - 2.

Now, Ic² + b²l

= I(- 2)² + (- 3)²l {Putting the values of b and c}

= I4 + 9l  

= I13l

= 13 units.

Therefore, Ic² + b²l = 13 units. (Answer)

5 0
3 years ago
Sarita showed the steps to solving the equation.
shtirl [24]

The option that explains Sarita's mistake is Sarita’s solution is correct. She made an error in her verification.

<h3>What was Sarita's mistake?</h3>

The given equation is: 5(x - 3) + 7(x + 4) = 73

In order to determine the value of x, take the following steps:

1. Apply the Distributive property:

5x - 15 + 7x + 28 = 73

2. Add similar terms together:

12x  + 13 = 73

3. Combine similar terms:

12x = 73 - 13

4. Add similar terms

12x = 60

5. Divide both sides of the equation by 12

x = 60 / 12

x = 5

In order to verify the answer, substitute for x in the given equation :

5(5 - 3) + 7(5 + 4) = 73

5(2) + 7(9) = 73

10 + 63 = 73

73 = 73

Please find attached the complete question. To learn more about equations, please check: brainly.com/question/14446120

#SPJ1

6 0
1 year ago
Find the GCF of 40, 55, and 72.
Papessa [141]

Answer: 5

Step-by-step explanation:

8 0
3 years ago
What are the x-intercepts of x^2– 3x = 4?
Sindrei [870]

Answer:

x^2-3x=4

x^2-3x-4=0

x^2-4x+x-4=0

x(x-4)+1(x-4)=0

(x+1)(x-4)=0

x=-1,4

x- intercepts in the point (-1,0) and (4,0)

Step-by-step explanation:

3 0
3 years ago
Square root of 32 x square root of 1 over 18
lisov135 [29]
<h3>Solution:</h3>

\sqrt{32}  \times  \sqrt{ \frac{1}{18} }  \\  =  \sqrt{32}  \times  \frac{ \sqrt{1} }{ \sqrt{18} }  \\  =  \sqrt{32}  \times  \frac{1}{ \sqrt{18} }  \\  =  \frac{\sqrt{2 \times 2 \times 2 \times 2 \times 2}}{ \sqrt{2 \times 3 \times 3} }   \\  =  \frac{ \sqrt{ {2}^{2}  \times  {2}^{2}  \times 2} }{ \sqrt{2 \times  {3}^{2} } }  \\  =  \frac{2 \times 2 \times  \sqrt{2} }{3 \times  \sqrt{2} }  \\  =  \frac{4 \times  \sqrt{2} }{3 \times  \sqrt{2} }  \\  =  \frac{4}{3}

<h3>Answer:</h3>

\frac{4}{3}

<h3>Hope it helps...</h3>

ray4918 here to help

7 0
2 years ago
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