Ask question

Ask question

All categories

3 years ago

15

Mrs. Smith is creating a rectangular flower bed such that the width is half of the

1 answer:

Brilliant_brown [7]3 years ago

6 0

Answer:

As for this problem, we will first establish that the length of the flower bed be represented as x, the width of the flower bed be represented as x/2 ,and the area of the flower bed be taken as it is since it is given. We then follow the formula for area which is length multiplied to width which is:

A = LW

we then substitute them

34 square feet = x (x/2)

now all we need to do is find x first.

34 square feet = x squared / 2

now do a cross multiplication

68 square feet = x squared

then get the square root of both sides

8.246 feet = x

Since x is equal to the length of the flower bed, all we have to do to get the width of it is to divide it by 2. So...

W = x/2

W = 8.246 feet / 2

W = 4.123 feet

And since the problem asked it to find the width of the flower bed to the nearest tenth of a foot, the answer would be 4.1 ft.

You might be interested in

Please help IM a NOT opErAted tO do THIs

stealth61 [152]

I have absolutely no idea goodluck with that

Now the reasoning of me not knowing is because my brain capacity is very low im just tryna get points I hope you find out the answer to that question good day sir

8 0

2 years ago

Read 2 more answers

What is the value of f(x)= 9^x when x=-2?<br> A) 1/8<br> B) 81<br> C) 1/18<br> D) 18

lions [1.4K]

Substitute -2 in for x and get (9)^-2
Flip the equation so that the exponent is positive and get 1/9^2
Work it out 1/(9*9) = 1/81

4 0

3 years ago

Find the mass of the triangular region with vertices (0, 0), (3, 0), and (0, 1), with density function ρ(x,y)=x2+y2.

ololo11 [35]

Since density is the ratio of mass to (in this case) area, we can find the mass of the triangular region $\mathcal T$ by computing the double integral of the density function over $\mathcal T$ :

$\mathrm{mass}=\displaystyle\iint_{\mathcal T}\rho(x,y)\,\mathrm dx\,\mathrm dy$

The boundary of $\mathcal T$ is determined by a set of lines in the $x,y$ plane. One way to describe the region $\mathcal T$ is by the set of points,

$\mathcal T=\left\{(x,y)\mid0\le x\le 3\,\land\,0\le y\le1-\dfrac x3\right\}$

So the mass is

$\mathrm{mass}=\displaystyle\int_{x=0}^{x=3}\int_{y=0}^{y=1-x/3}(x^2+y^2)\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_{x=0}^{x=3}\left(x^2y+\frac{y^3}3\right)\bigg|_{y=0}^{y=1-x/3}\,\mathrm dx$

$=\displaystyle\int_{x=0}^{x=3}\left(x^2\left(1-\frac x3\right)+\frac{\left(1-\frac x3\right)^3}3\right)\,\mathrm dx$

$=\displaystyle\frac1{81}\int_0^3(27-27x+90x^2-28x^3)\,\mathrm dx=\frac52$

6 0

3 years ago

Quadrilateral QRST is inscribed in circle W as shown below. The measure of ∠QRS is 12 degrees less than three times the measure

Tju [1.3M]

<u>Corrected Question</u>

Quadrilateral QRST is inscribed in circle W as shown below. The measure of ∠QRS is 12 degrees less than three times the measure of ∠QTS and

mRQT=mRST .

(a)Determine the measure of Angle QTS .

(b)What is the common measure of angles RQT and RST ?

Answer:

(a)48 degrees

(b)90 degrees

Step-by-step explanation:

Theorem: Opposite angles of a cyclic quadrilateral are supplementary.

(a)

Let the measure of ∠QTS=x

Therefore: m∠QRS=3x-12

∠QTS and ∠QRS are opposite angles of a cyclic quadrilateral. By the theorem above:

x+3x-12=180

4x=180+12

4x=192

x=48 degrees

The measure of angle QTS is 48 degrees.

(b)Since mRQT=mRST

mRQT and mRST are opposite angles of a cyclic quadrilateral

Therefore:

mRQT+mRST=180 degrees

2mRQT=180

mRQT=90 degrees

Therefore, the common measure of RQT and RST is 90 degrees.

6 0

3 years ago

Assuming that the value of x is 4, and the value of y is 6, what is the value of the following expression? (x - y)**2 > y Typ

DochEvi [55]

Considering the given expression and the numerical values, it is found that it's value is False.

<h3>What is the expression given?</h3>

The expression used in this question is given as follows:

$(x - y) \times 2 > y$

The values considered are x = 4 and y = 6, hence:

$(6 - 4) \times 2 > 6$

$4 > 6$

Hence, it is a False expression, as 4 is less than 6.

More can be learned about expressions at brainly.com/question/25537936

5 0

2 years ago