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3 years ago

Mrs. Smith is creating a rectangular flower bed such that the width is half of the

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

6 0

Answer:

As for this problem, we will first establish that the length of the flower bed be represented as x, the width of the flower bed be represented as x/2 ,and the area of the flower bed be taken as it is since it is given. We then follow the formula for area which is length multiplied to width which is:

A = LW

we then substitute them

34 square feet = x (x/2)

now all we need to do is find x first.

34 square feet = x squared / 2

now do a cross multiplication

68 square feet = x squared

then get the square root of both sides

8.246 feet = x

Since x is equal to the length of the flower bed, all we have to do to get the width of it is to divide it by 2. So...

W = x/2

W = 8.246 feet / 2

W = 4.123 feet

And since the problem asked it to find the width of the flower bed to the nearest tenth of a foot, the answer would be 4.1 ft.

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Plz help and thank you

avanturin [10]

Answer:

THE EQUATION OF THE LINE IS X=4

Step-by-step explanation:

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4 0

3 years ago

Find the mean please

zysi [14]

Answer:

199.5

Step-by-step explanation:

Add all the numbers and divide by number of responses aka 6

6 0

3 years ago

Solutes in the bloodstream enter cells through osmosis, which is the diffusion of fluid through a semipermeable membrane. Let C

kow [346]

Answer:

since the rate at which concentration inside the cell is proportional to the difference in the concentration of the solute in the blood stream and the concentration within the cell, then the rate of change of concentration within the cell is equals to K(L-C).

Thus, the required differential equation is Δc/Δt = K( L - C ).

Step-by-step explanation:

4 0

3 years ago

Use cramers Rule to solve the following system:

Jet001 [13]

Answer:

The solution to the system is $x=1$ , $y=-2$ and $z=-5$

Step-by-step explanation:

Cramer's rule defines the solution of a system of equations in the following way:

$x= \frac{D_x}{D}$ , $y= \frac{D_y}{D}$ and $z= \frac{D_z}{D}$ where $D_x$ , $D_y$ and $D_z$ are the determinants formed by replacing the x,y and z-column values with the answer-column values respectively. $D$ is the determinant of the system. Let's see how this rule applies to this system.

The system can be written in matrix form like:

$\left[\begin{array}{ccc}5&-3&1\\0&2&-3\\7&10&0\end{array}\right]\times \left[\begin{array}{c}x&y&z\end{array}\right] = \left[\begin{array}{c}6&11&-13\end{array}\right]$

Then each of the previous determinants are given by:

$D_x = \left|\begin{array}{ccc}6&-3&1\\11&2&-3\\-13&10&0\end{array}\right|=199$ Notice how the x-column has been substituted with the answer-column one.

$D_y = \left|\begin{array}{ccc}5&6&1\\0&11&-3\\7&-13&0\end{array}\right|=-398$ Notice how the y-column has been substituted with the answer-column one.

$D_z = \left|\begin{array}{ccc}5&-3&6\\0&2&11\\7&10&-13\end{array}\right|=-995$

Then, substituting the values:

$x= \frac{D_x}{D}=\frac{199}{199}\\ x=1$

$x= \frac{D_y}{D}=\frac{-398}{199}\\ y=-2$

$x= \frac{D_z}{D}=\frac{-995}{199}\\ x=-5$

3 0

3 years ago

4. An airplane at T(80,20) needs to fly to both U(20,60) and V(110,85). What is the shortest possible distance for the trip?

damaskus [11]

The distance formula for two points in a plane is
D=sqrt( (x1-x2)^2 + (y1-y2)^2 )
From T to U
D= sqrt((80-20)^2 + (20-60)^2) = 72.11
Then flying from U to V
D= sqrt((20-110)^2 + (60-85)^2) = 93.4
So T to U to V = 72.11+93.4 = 165.5
BUT checking also T to V to U
From T to V
D= sqrt((80-110)^2 + (20-85)^2) = 71.6
Then from V to U
D= sqrt((110-20)^2 + (85-60)^2) = 93.4
So from T to V to U = 165
Pretty much the same both directions
So yes the answer is A

4 0

3 years ago