I NEED HELP ASAP PLEASE

Peta makes a painting on a parallelogram-shape canvas. What is the area of this parallelogram? 1.53 ft² 3.74 ft² 5.27 ft² 22.09

Nikitich [7]

The answer is 5.27ft²

6 0

3 years ago

What is this answer?

dusya [7]

1/84

1/7 ÷ 12

turn 12 into 1/12 bc your dividing fractions and turn the division symbol to multiplication

1/7 × 1/12

answer: 1/84

4 0

3 years ago

PLEASE HELp!

NISA [10]

Answer:

B. 37

Step-by-step explanation:

You first find the median of the entire set which is 46. Then find the median of the lower half of the set which is 27. Then find the median of higher part of the data set which is 64. Then you do 64-27=37.

Hope that helped a little bit :)

5 0

4 years ago

If the probability of an event is 5/9, what is the probability of its complementary event

Arte-miy333 [17]

1-5/9=4/9.............

5 0

4 years ago

An automobile owner found that 20 years ago, 72% of Americans said that they would prefer to purchase an American automobile. He

LenaWriter [7]

Answer:

$z=\frac{0.884 -0.72}{\sqrt{\frac{0.72(1-0.72)}{43}}}=2.395$

Now we can find the p value taking incount that we are using a bilateral test

$p_v =2*P(z>2.395)=0.01662$

Since the p value is lower than the significance level of 0.1 we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of Americans that they would prefer an American automobile is significantly different from 0.72 and then the claim is correct

Step-by-step explanation:

Information given

n=43 represent the random sample taken

X=38 represent the Americans who they would prefer an American automobile

$\hat p=\frac{38}{43}=0.884$ estimated proportion of Americans that they would prefer an American automobile

$p_o=0.72$ is the value that we want to check

$\alpha=0.1$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to verify if the percentage of Americans that they would prefer an American automobile today differs from 72%, then the system of hypothesis are:

Null hypothesis: $p=0.72$

Alternative hypothesis: $p \neq 0.72$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the data given we got:

$z=\frac{0.884 -0.72}{\sqrt{\frac{0.72(1-0.72)}{43}}}=2.395$

Now we can find the p value taking incount that we are using a bilateral test

$p_v =2*P(z>2.395)=0.01662$

Since the p value is lower than the significance level of 0.1 we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of Americans that they would prefer an American automobile is significantly different from 0.72 and then the claim is correct

5 0

3 years ago