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algol [13]
3 years ago
7

What's 76×32÷5+(19×92)-15×2? Need help ASAP​

Mathematics
2 answers:
arsen [322]3 years ago
6 0

Answer:

2204.4

Step-by-step explanation:

Okay so we want to always use order of operations: PEMDAS

Sop first we do what is in the parenthesis. 19*92 is 1748.

Now, going from left to right, we do multiplication and division. 76*32 is 2432. Then we divide that by 5 to get 486.4. And the last bit is 15*2 which is 30.

Your equation now is 486.4+1748-30.

The final answer is 2204.4

Aleksandr-060686 [28]3 years ago
5 0

Answer:

2204.04

Step-by-step explanation:

Follow PEMDAS:

Parenthesis

Exponent

Multiply

Divide

Add

Subtract

----------------------------------------------------------------------------

Since 19 and 92 are in parenthesis, we do those two first.

(19*92)

1,748

76 * 32 / 5 + 1,748 - 15 * 2

Next is multiply.

76 * 32

2,432

2,432 / 5 + 1,748 - 15 * 2

-15 * 2

-30

2,432 / 5 + 1,748 - 30

Now is dividing.

2,432 / 5

486.4

486.4 + 1,748 - 30

Now you add and subtract (left to right).

486.4 + 1,748

2234.4

2234.4 - 30

2204.4

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Find the distance between the points (7,-5) and (2, -5).
vazorg [7]

Answer:

15.62 units.

Step-by-step explanation:

To commence with, find for the vector.

Points = (7,-5) and (2,-5)

7 + 2

-5 + -5

12

-10

Vector = 12

-10

Magnitude = y² + x²

Points = (12,-10)

-10² + 12²

100 + 144

244

Square root of 244 is 15.62

Therefore, the distance between the points is 15.62 units.

Hope it helps.

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What is b over 7 when b= 14
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The answer is -7....
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A sandbag is released from a hot air balloon that is 400ft above the ground. Using the falling object model, h = –16t2 + s, wher
Aleonysh [2.5K]

<u>Answer</u>:

It takes 5 seconds for the sandbag to hit the ground

<u>Explanation</u>:

Given:

Height at which the sand bag is released from the hot air balloon= -400 f t

To find:

Time taken for the sandbag to hit the ground, t =?  

Solution:

The initial height =s

Initially the height will be 0

Hences=0

the falling object model equation  

h=-16 t^{2}+s

Substituting the values we get,

h=-16 t^{2}+s

400=16 t^{2}

t^{2}=\frac{400}{16}

t^{2}=25

t=\sqrt{25}

t=5 \text { seconds }

Result:

Thus it takes 5 seconds for the sandbag to hit the ground

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