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nordsb [41]
3 years ago
5

Josh brought 4 small spinach pies to his baseball team

Mathematics
1 answer:
tangare [24]3 years ago
7 0

Answer:

3/5+3/5= 6/5= 1.1 because if he gave 2 holes away he only has 3/5 of 2 pies left add dows that together and u have a improper fraction 6 goes into 5 once leaving u with 0.1 add the one from the whole pie u and and u have 1.1

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What is the third quartile, Q3, of the following distribution?
GREYUIT [131]

Answer:

The third quartile is:

Q_3=29

Step-by-step explanation:

First organize the data from lowest to highest

4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44

Notice that we have a quantity of n = 20 data

Use the following formula to calculate the third quartile Q_3

For a set of n data organized in the form:

x_1, x_2, x_3, ..., x_n

The third quartile is  Q_3:

Q_3=x_{\frac{3}{4}(n+1)}

With n=20

Q_3=x_{\frac{3}{4}(20+1)}

Q_3=x_{15.75}

The third quartile is between x_{15}=29 and x_{16}=29

Then

Q_3 =x_{15} + 0.75*(x_{16}- x_{15})

Q_3 =29 + 0.75*(29- 29)\\\\Q_3 =29

5 0
3 years ago
Read 2 more answers
Find the area of the regular polygon
Vsevolod [243]

Answer:

433.4

Step-by-step explanation:

Height will be (14/2)/tan36 which is 9.63, then area for one triangle is 1/2*hb which is .5*9.63*7 is 43.34, times 10 you get 433.4

7 0
3 years ago
WILL GIVE BRAINLIEST IMMEDIATELY!!!!!!!
Bas_tet [7]

Answer:

B

Step-by-step explanation:

When flipping, the y-levels of E' and F' do not change, meaning that as they are transferred across the y-axis, they keep their parallel to the original points.

6 0
3 years ago
Anna is no more than 3 years older than 2 times Jamie’s age. Jamie is at least 14 and Anna is at most 35. Which system of linear
Afina-wow [57]
A < 3 + 2j
j >= 14 
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6 0
3 years ago
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Which values are possible rational roots of 4x3+9x2−x+10=0 according to the rational root theorem? Select each correct answer. ±
chubhunter [2.5K]

Answer:

±2

Step-by-step explanation:

For simplicity let's take a look at a general third order polynomial:

ax^3 + bx^2 + cx + d.  In this particular case,

rational roots have the form ±d/±a.  Note that these are fractions/ratios.  Beyond that, we factor d and choose numerators ±(all possible whole number factors of d, dividing these results by all possible factors of a.

Looking at 4x^3 + 9x^2 - x + 10 = 0, we see that d = 10 and that factors of d include ±1, ±2, ±5 and ±10.  a = 4 and factors of a include ±1, ±2, ±4.

So, any rational roots of the given polynomial will stem from the possible rational roots

±1    ±2    ±5    ±10    ±1    ±2    ±5    ±10

--- , ----- , -----, ------- , ---- , ----- , --- , ------ , and so on,

±1    ±1     ±1      ±1      ±2    ±2   ±2     ±2

until you have used up all of the possible factors of 10 and all of the possible factors of 4.  

Of the four possible rational roots you have shared, only ±2 (which would actually be ±2 / ±1) is acceptable.

4 0
3 years ago
Read 2 more answers
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