Answer:
f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.
Step-by-step explanation:
The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.
* if x>1, then x-1>0.
* Also since the parabola opens up, then y>5.
So let's solve y=(x-1)^2+5 for x.
Subtract 5 on both sides:
y-5=(x-1)^2
Take square root of both sides:
Plus/minus sqrt(y-5)=x-1
We want x-1>0:
Sqrt(y-5)=x-1
Add 1 on both sides:
Sqrt(y-5)+1=x
Swap x and y:
Sqrt(x-5)+1=y
x>5
y>1
16 x 8 = 128 square feet (area of rectangle)
shaded:
8 x 2 = 16
10 x 1 = 10
1/2 (3)(10) = 15
total shaded area: 16+10+15 = 41 square feet
total non-shaded area = 128 - 41 = 87 square feet
answer
area of the shaded region = 41 square feet
area of the non - shaded region = 87 square feet
Answer:
Y=2x-7
Step-by-step explanation:
Answer:
55+55+52+52=214
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