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pentagon [3]
3 years ago
15

What was Anton van Leeuwenhoek's contribution in the development of cell theory?

Biology
2 answers:
rosijanka [135]3 years ago
3 0

He developed and improved the microscope. He was also the first to discover single-cell organisms that he called animalcules.

wlad13 [49]3 years ago
3 0

Answer: He invented the first practical microscopes which was used to see bacterial cell.

Explanation:

Microscopic study was done by Anton van Leeuwenhoek who was a draper and he had a great interest in microscope. This helped in mixing the lens and making a microscope which was used to see cell.

This microscope had a magnification of 270 x, which was of great help when visualizing such a small organism that was not seen by naked eyes.

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Q:- In dogs, the Mexican hairless phenotype never breeds true. When Mexican hairless are interbred the offspring are 2/3 hairles
drek231 [11]

Explanation:

The problem says that the hairless phenotype never breeds true. That means that it's not the result of a homozygous genotype (H₁H₁ or H₂H₂), so it is caused by the heterozygous genotype (H₁H₂).

The <u>expected </u>offspring from the cross between two Mexican hairless would be:

<h3>P                 H₁H₂  x  H₁H₂</h3><h3>F1    1/4 H₁H₁,  2/4 H₁H₂ and 1/4 H₂H₂.</h3>

And the <u>expected</u> phenotypic ratio 3:1. However, the observed offspring shows a 2:1 ratio. What's happening?

If the observed phenotypic ratio in the offspring of a monohybrid cross (a single gene with two alleles) is 2:1, we can suspect that one of the genotypes is lethal in homozygosis and therefore does not appear in the progeny (the puppies are born dead).

If we proposed that the H₂ allele is lethal in homozygosis, then:

  • The H₁H₁ genotype would cause normal puppies --> 1
  • The H₁H₂ genotype would cause hairless puppies --> 2
  • The H₂H₂ is lethal and causes the death of puppies --> 0

The phenotypic ratios change to 2:1, as observed in the experiment.

7 0
3 years ago
How does the available staff influence the selection of either continuous electronic or intermittent auscultation as the fetal-m
kondaur [170]

Answer:

The options

a. There must be a 1:1 nurse-to-patient ratio regardless of the method used.

b. Staffing patterns do not influence fetal monitoring choices.

c. Use of intermittent auscultation requires a lower nurse-to-patient ratio.

d. More nurses are needed when electronic fetal monitoring is used because of increased medical interventions.

The ANSWER is c.

c. Use of intermittent auscultation requires a lower nurse-to-patient ratio.

Explanation:

a. There must be a 1:1 nurse-to-patient ratio regardless of the method used.❌

A one-to-one ratio is important at the second phase of labor or in occurrence of a high-risk condition, irrespective of the monitoring method applied.

b. Staffing patterns do not influence fetal monitoring choices.❌

Staffing patterns do have an influence in conserving safe monitoring routine of the labor patient.

c. Use of intermittent auscultation requires a lower nurse-to-patient ratio.✔

Intermittent auscultation is largely staff-intensive.

d. More nurses are needed when electronic fetal monitoring is used because of increased medical ❌

Reduced nursing time is needed when carrying out electronic monitoring, this will allow the nurse to have increased time for educating, encouraging and supporting the laboring woman.

6 0
3 years ago
What cell organelle is responsible for making the vesicles for exocytosis to occur?
Dmitry [639]

Answer:

cell membrane i think

Explanation:

4 0
3 years ago
The higher the ____ content of a dna, the ____ the strength of the interchain interactions, and the ____ the melting temperature
castortr0y [4]

The higher the GC content of a DNA, the higher the strength of the interchain interactions, and the higher the melting temperature.

DNA is Deoxyribonucleic Acid. It is the genetic material in maximum of the organisms. The DNA is a polymer made from nucleotides (sugar, nitrogenous bases and phosphate group). It is composed of two strands of phosphate and sugar backbone in an antiparallel direction. The nitrogenous bases present in DNA are Adenine (A), Thymine (T), Guanine (G) and Cytosine (C).

GC content refers to the total amount of Guanine and Cytosine present in the DNA. Since there exists a triple bond between G and C, more percentage of them provides strength to DNA. That is why high GC content denotes high melting temperature of DNA.

To know more about DNA and GC content, here

brainly.com/question/13052467

#SPJ4

3 0
2 years ago
When Charles Darwin set sail on the HMS Beagle, what did he and most of his contemporary scientists think about the origin of sp
Rama09 [41]

Answer:

Most scientists, including Darwin, thought each species was specially created by God in its present form and did not change over time.

Explanation:

3 0
3 years ago
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