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3 years ago

Increasing the speed of an object blank its potential energy

Physics

1 answer:

ella [17]3 years ago

7 0

There is no direct connection between the speed of an object and its potential energy.

UNLESS the object is falling, and it's GETTING its speed FROM its potential energy. If that's what's going on, then of course if the speed increases, the object's kinetic energy increases, and that increase has to come from using up some of the potential energy.

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Toon Train is traveling at the speed of 10 m/s at the top of a hill. Five seconds later it reaches the bottom of the hill and is

Naddika [18.5K]

Answer:

the rate of acceleration of the train is 4 m/s²

Explanation:

Given;

initial velocity of the train, u = 10 m/s

change in time of motion, dt = 5 s

final velocity of the train, v = 30 m/s

The rate of acceleration of the train is calculated as;

$a = \frac{dv}{dt} = \frac{v-u}{dt} = \frac{30-10}{5} = \frac{20}{5} = 4 \ m/s^2$

Therefore, the rate of acceleration of the train is 4 m/s²

5 0

3 years ago

A 2.00 kg block hangs from a spring balance calibrated in Newtons that is attached to the ceiling of an elevator.(a) What does t

tresset_1 [31]

Answer:

Part a)

$Reading = 2.00 kg$

Part b)

$Reading = 2.00 kg$

Part c)

$Reading = 4.04 kg$

Part d)

from t = 0 to t = 4.9 s

so the reading of the scale will be same as that of weight of the block

Then its speed will reduce to zero in next 3.2 s

from t = 4.9 to t = 8.1 s

The reading of the scale will be less than the actual mass

Explanation:

Part a)

When elevator is ascending with constant speed then we will have

$F_{net} = 0$

$T - mg = 0$

$T = mg$

So it will read same as that of the mass

$Reading = 2.00 kg$

Part b)

When elevator is decending with constant speed then we will have

$F_{net} = 0$

$T - mg = 0$

$T = mg$

So it will read same as that of the mass

$Reading = 2.00 kg$

Part c)

When elevator is ascending with constant speed 39 m/s and acceleration 10 m/s/s then we will have

$F_{net} = ma$

$T - mg = ma$

$T = mg + ma$

Reading is given as

$Reading = \frac{mg + ma}{g}$

$Reading = 2.00\frac{9.81 + 10}{9.81}$

$Reading = 4.04 kg$

Part d)

Here the speed of the elevator is constant initially

from t = 0 to t = 4.9 s

so the reading of the scale will be same as that of weight of the block

Then its speed will reduce to zero in next 3.2 s

from t = 4.9 to t = 8.1 s

The reading of the scale will be less than the actual mass

3 0

3 years ago

Atoms gain the same electron configuration as noble gases by

Nesterboy [21]

Thr answer is D losing or gaining electons

3 0

3 years ago

The moon has a smaller mass than the Earth. If you were able to travel to the moon your weight would

Lelu [443]

Answer:

for example, a person weighing 100kg when on the moon only has 38kg is not wrong because the scale is just a device to measure weight, not mass, people have taken advantage of gravity to measure the weight of objects, so I think Your actual weight doesn't change, what changes is gravity and acceleration

Explanation:

3 0

3 years ago

The speed of propagation of electrical signals in a nerve cell depends on the diameter of the axon (nerve fiber). If the nerve c

gayaneshka [121]

Answer:

61 ms

Explanation:

Given that

Length of the nerve call connecting the spinal cord to your feet, s is 1.1 m

Speed of the impulse of the nerve, v = 18 m/s

Time taken by the nerve to travel the distance, t = ?

In solving this, we'd apply the very most basic formula in physics. Formula of speed, with respect to time and distance.

Speed, v = distance, s / time, t

time, t = distance, s / speed, v

time, t = 1.1 / 18

time, t = 0.061 s, converting to milliseconds, we have, time, t = 61 ms

6 0

3 years ago

Increasing the speed of an object blank its potential energy ​

Increasing the speed of an object blank its potential energy