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Andrews [41]
3 years ago
12

The probability that John receives junk mail is 11%. If he receives 94 pieces of mail in a week ,about how many of them can he e

xpect to be junk mail?
Mathematics
1 answer:
Papessa [141]3 years ago
4 0

Hi!

The answer is : 11% * 94 = 0,11 * 94 = 10,34, so about 10 from 94 are junk

Hope this helps!

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Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure
Marina CMI [18]

Answer:

a) P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

b) P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

X \sim N(0.12,0.009)  

Where \mu=0.12 and \sigma=0.009

We are interested on this probability

P(0.11

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want this probability:

P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

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3 years ago
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Answer:

Step-by-step explanation:

In terms of distance, a decreasing slope means a slowing speed, which leads to a shorter distance.

7 0
3 years ago
Which of the following best describes the type of probability used in the
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Awnser is C. Random cuz thats how i chose this answer... its was random

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Answer:

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Step-by-step explanation:

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For breakfast, Sarah can choose eggs, granola or oatmeal as a main course, and orange juice or milk for a drink. Sarah says that
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Answer:

The explanation is given below

Step-by-step explanation:

Her error is that she multiplied the possibilities of her meal that involves eggs with milk, granola & oatmeal but the possibilities involves orange juice with egg and granola & oatmeal

Now

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So, the sample space is

= 3 + 3

= 6 outcomes  

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