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3 years ago

8

Please show the work for it as well thank you

1 answer:

AlexFokin [52]3 years ago

4 0

Answer:

2x^4+4x^2+2

Step-by-step explanation:

f(x) = x^2+1

g(x) = 2x^2

g(f(x))=

Replace x in the function g(x) with the function f(x)

=2( x^2+1)^2

= 2( x^2 +2x^2 +1)

= 2x^4+4x^2+2

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Compound Inequalities <br> (Help)

sladkih [1.3K]

- 8x + 44 ≥ 60
- 8x ≥ 60 - 44
- 8x ≥ 16
x ≤ - 2

- 4x + 50 < 58
- 4x < 58 - 50
- 4x < 8
x > - 2

Now put the two together. Logically, these two answers since a number cannot be both less than AND greater than - 2.

Your answer should be no solution.

5 0

3 years ago

Equation<br><img src="https://tex.z-dn.net/?f=%28z%20%2B%20%20%5Cfrac%7B6%7D%7B7%7D%20%29%20%2B%20%20%5Cfrac%7B2%7D%7B14%7D%20%2

ddd [48]

Given:

The equation is

$\left(z+\dfrac{6}{7}\right)+\dfrac{2}{14}=-1$

To find:

The solution of the given equation.

Solution:

We have,

$\left(z+\dfrac{6}{7}\right)+\dfrac{2}{14}=-1$

It can be written as

$\left(z+\dfrac{6}{7}\right)+\dfrac{1}{7}=-1$

$\left(z+\dfrac{6}{7}\right)=-1-\dfrac{1}{7}$

Multiply both sides by 7.

$7z+6=-7-1$

$7z+6=-8$

$7z=-8-6$

$7z=-14$

Divide both sides by 7.

$z=\dfrac{-14}{7}$

$z=-2$

Therefore, the value of z is -2.

5 0

2 years ago

Suppose the lengths of two sides of a right triangle are represented by 2x and 3 (x + 1), and the longest side is 17 units. Find

densk [106]

Answer:

x=4

Step-by-step explanation:

<u>Step 1</u>:-

given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.

AB = 2x and BC = 3(x+1) and longest side AC= 17

by using Pythagoras theorem

$AC^2 = AB^2 + BC^2$

<u>step 2:-</u>

The hypotenuse is longest side is AC = 17 units

(17)^2 = 4x^2 +9(X+1)^2

on simplification, we will use formula

$(a + b)^2 = a^2 +2ab+b^2$

289 = 4x^2 +9(x^2+2x+1)

$13x^2 +18x-280 = 0$

finding factors 70 X 52 = 3640

$13x^2 +70x-52x-280 = 0$

$13x^2 -52x+ 70x-280 = 0$

Taking common , we get

13x(x-4)+70(x-4)=0

x-4=0 and 13x+70=0

x=4 and $13x =-70$

x=4 and $x=\frac{-70}{13}$

we can not choose negative value so x value is 4

Final answer:- x = 4

<u>verification:-</u>

<u></u> $AC^2 = AB^2 + BC^2$ <u></u>

289 = 4(4)^2+9(4+1)^2

289 = 64 +9(25)

289=289

6 0

3 years ago

Read 2 more answers

******Please help me help please help me ******

Veseljchak [2.6K]

Answer:

36

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Eight more than three times a number is equal to the number.<br> What is the number

hodyreva [135]

Answer:

-4

Step-by-step explanation:

-4(3) = -12

-12 + 8 = -4

3 0

2 years ago

Read 2 more answers