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3 years ago

Anyone help with math??

Mathematics

1 answer:

Triss [41]3 years ago

4 0

Answer:

I can maybe!

OK, sorry it took me so long I wanted to make sure I gave you the best answer I could so I had to think a little. Anyway. If I had to pick one I would choose...

D. The value of g(x) is determined by the value of h times x.

I really hope this helps! I tried my best!

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What si the answer to the following question y = x ^2 + 3 x + 3

Paul [167]

Answer: Solve the equation for

by finding

, and

of the quadratic then applying the quadratic formula.

x = −3−√−3+4y2x=−3+√4y−32

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

SOMEONE PLEASE HELP ME PLEASE

sukhopar [10]

BDE=70
EDG=50
FDG=60
CDA=85

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3 years ago

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Owen runs a pet store that sells rabbits. He wants to ensure he has more than 1 pound of dry food for every four rabbits he has

Lana71 [14]

Answer:

B) Owen can have a maximum of 22 rabbits in the store.

Step-by-step explanation:

Consider:

"He wants to ensure he has more than 1 pound of dry food for every four rabbits he has in the store."

It means, at least 0.25 pounds per rabbit. (1 pound divided by four)

"He currently has 5.7 pounds of dry food."

Inequality (r is the number of rabbits):

$5.7\leq 0.25r\\22.8\leq r$

According to the inequality, he can only have a maximum of 22 rabbits.

7 0

4 years ago

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Will name brainliest please help me.

Ede4ka [16]

Answer:

CD = 9

Step-by-step explanation:

ΔADE is similar to ΔBCD

Such that:

AD is similar to CD

BD is similar to ED

AE is similar to BC

Taking the proportion of their sides to find the unknown sides CD

=> $\frac{6}{2} = \frac{CD}{3}$

Cross Multiplying

=> 2(CD) = 3*6

=> CD = 18/2

=> CD = 9

3 0

4 years ago

Please help

lys-0071 [83]

Part 1
1) The positive integers -----------> D.) The natural numbers
2.) An ordering of quantities -----------> B.) A sequence
3.) 2, 4, 8, 16, . . ., 256 -----------> A.) An example of a finite sequence
4.) 1, 3, 5, 7, . . . -----------> E.) An example of an infinite sequence
5.) No first term is available -----------> C.) The reason the numbers . . . -4, -2, 0, 2, 4, . . . are not a sequence
Part 2
$a_n=n^2+2\\ a_1=1+2=3\\ a_2=4+2=6\\ a_3=9+2=11\\ a_4=16+2=18\\ a_5=25+2=27$
The answers is A.
Part 3
$a_n=-1(\frac{1}{3})^{n-1} \\ a_1=-1(\frac{1}{3})^{1-1}=-1\\ a_2=-1(\frac{1}{3})^{2-1}=-\frac{1}{3}\\ a_3=-1(\frac{1}{3})^{3-1}=--\frac{1}{9}\\ a_4=-1(\frac{1}{3})^{4-1}=--\frac{1}{27}\\ a_5=-1(\frac{1}{3})^{5-1}=--\frac{1}{81}\\$
The answers is B.
Part 4
The pattern in this sequence is:
$a_n=2a^nb^{n-1}$
Let's list first six terms:
$a_n=2a^nb^{n-1}\\
a_1=2a^1b^0=2a\\
a_2=2a^2b^1=2a^2b\\
a_3=2a^3b^2\\
a_4=2a^4b^3\\
a_5=2a^5b^4\\
a_6=2a^6b^5\\$
This is a infinite sequence. The patern is obvious and we could find any term within the sequence.

5 0

3 years ago