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den301095 [7]
4 years ago
8

Which of the following are properties of substances with matter? (2 points)

Chemistry
1 answer:
kramer4 years ago
7 0
The answer is A. Hope this helps
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Please give me the correct answer 100 percent please any answer will be good
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The correct answer is C. Consume food


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Why do animals need carbohydrates in their diets
Sever21 [200]

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Carbohydrates are energy-providing feed components composed of carbon, hydrogen, and oxygen. They should make up about 75 percent of an animal's diet. The energy they provide powers muscular movements. Carbohydrates also produce the body heat that helps keep the animal warm.

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3 years ago
How many grams of CuSO4 • 5H2O do you need to make 0.8 L of a 0.6 M solution
Bumek [7]
<h3><u>Unders</u><u>tanding</u><u> </u><u>the</u><u> </u><u>conc</u><u>ept</u><u>:</u><u>-</u></h3>

Here the concept of Molarity used .We will put the formula of Molarity then we find moles of copper sulphate .Then we can find the.Given weight of Copper sulphate.So let's do

<h3>Solution:-</h3>

  • Volume of Solvent=0.8L
  • Molarity=0.6M

We know

\boxed{\sf Molarity=\dfrac{Moles\:of\: solute}{Volume\:of\: Solvent \:in\;L}}

\\ \rm\longmapsto Moles\:of\: solute=Molarity\times Volume\:of\: Solvent\:in\:L

\\ \rm\longmapsto Moles\:of\: Solute=0.8(0.6)

\\ \rm\longmapsto Moles\:of\: Solute=0.48mol

Now

Molar Mass of Solute:-

\\ \rm\longmapsto CuSO_4.5H_2O

\\ \rm\longmapsto 65u+32u+4(16u)+5(2\times 1u+16u)

\\ \rm\longmapsto 96u+64u+5(2+16)

\\ \rm\longmapsto 160u+90u

\\ \rm\longmapsto 250u

\\ \rm\longmapsto 250g/mol

Now

\boxed{\sf No\:of\:moles=\dfrac{Given\:Mass}{Molar\:Mass}}

\\ \rm\longmapsto Given\:Mass=No\:of\:Moles\times Molar\:Mass

\\ \rm\longmapsto Given\:Mass=250(0.48)

\\ \rm\longmapsto Given\:Mass=120g

8 0
3 years ago
Co(g) + 2 h2 --&gt; ch3oh 2.50 g of hydrogen is reacted with 30.0 l of carbon monoxide at stp. 1. what is the limiting reactant?
Lemur [1.5K]
CO(g) +2H2--->CH3OH
2.50g H2*1mol/2g=1.25 mol H2
30.0L CO*1mol/22.4L=1.34 mol CO,
according to reaction 1 mol CO needs 2 mol H2,so 1.34 mol CO need 2.68 mol H2, so 1) limiting teactant is H2 (H)

2)1.25 mol CH3OH will be produced, 1.25 mol*32g/mol=40.0 g CH3OH
3) 1.25 mol H2 needs 0.625 g CO
1.34-0.625=0.715 g CO leftover

7 0
3 years ago
Read 2 more answers
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