Answer:
802.2 K
Explanation:
To solve this problem we can use the formula:
Where Tb is the boiling point (in K).
We already know the values of both ΔHvap and ΔSvap, so we calculate Tb:
- ΔHvap = 47.45 kJ·mol⁻¹ = 47.45x10³J·mol⁻¹
Tb = 47.45x10³J·mol⁻¹/59.15 J·mol⁻¹·K⁻¹
So the boiling point of the compound is 802.2 K (or 529 °C)
Hello there! A proton has a positive charge of (+1) and has a lesser mass compared to a neutron! Hope this helps! Have a great day!
A piece of paper is thin, slighlty smooth, can be white and smells woody. 500 g of butter has a density of 0.911 g/ml and has a volume thus of 548.85 ml. Butter has a color yellow and smells fatty. A glass of milk has a white color, sour smell and taste and the milk occupies the volume of glass. Candle is waxy, can be long or short, can have colors of different varieties and is cylindrical.
Let's begin with the basic values that will be used in the solution.
The formula of propane is C3H8. It is an alkane, a hydrocarbon with the general formula of CnH2n+2. Notice that hydrocarbons have only Carbon and Hydrogen atoms. Its molar mass (M) is 44 g.
Molar Mass Calculation is done as like that
C=12 g/mol, H=1 g/mol. 1 mole propane has 3 moles Carbon atoms and 8 mole Hydrogen atoms. M(C3H8)= 3*12+ 8*1= 44 g
Combustion reaction of hydrocarbons gives carbon dioxide and water by releasing energy. That energy is called as enthalpy of combustion (ΔHc°).
ΔHc° of propane equals -2202.0 kj/mol. Burning of 1 mole C3H8 releases 2202 kj energy. Minus sign only indicates that the energy is given out ( an exothermic reaction ).
Let's write the combustion reaction.
C3H8 + O2 ---> CO2 + H20 (unbalanced) ΔHc° = -2202 kj/mol
Now, we calculate mole of 20 kg propane. Convert kilogram into gram since we use molar mass is defined in grams.
mole=mass/molar mass ; n=m/M ; n= 20000 g /44 (g/mol)=454 mole
1 mole propane releases 2202 kj energy.
454 mole propane release 2202 kj *454= 1000909 kj
The answer is 1000909 kj.
